All categories

4 years ago

Please help me please!!!

Mathematics

1 answer:

AURORKA [14]4 years ago

8 0

Make one side length of the cube s.

V = lwh, but the length, width, and height are all s.

So V = sss, or s^3.

If it has a side length of 2^4, then 2^4 = 16.

V = s^3, or V = 16 times 16 times 16, which = 4096.

You might be interested in

If Cody is draining his hot tub which holds 1,400 gallons of water at a rate of 27 gallons a minute, what impact will it have on

leva [86]

After 18 minutes there will be 486 gallons of water drained.

3 0

3 years ago

Read 2 more answers

Yuri thinks that 3/4 is a root of the following function.

sineoko [7]

Given:

The polynomial function is

$q(x)=6x^3+19x^2-15x-28$

Yuri thinks that $\dfrac{3}{4}$ is a root of the given function.

To find:

Why $\dfrac{3}{4}$ cannot be a root?

Solution:

We have,

$q(x)=6x^3+19x^2-15x-28$

If $\dfrac{3}{4}$ is a root, then the value of the function at $\dfrac{3}{4}$ is 0.

Putting $x=\dfrac{3}{4}$ in the given function, we get

$q(\dfrac{3}{4})=6(\dfrac{3}{4})^3+19(\dfrac{3}{4})^2-15(\dfrac{3}{4})-28$

$q(\dfrac{3}{4})=6(\dfrac{27}{64})+19(\dfrac{9}{16})-\dfrac{45}{4}-28$

$q(\dfrac{3}{4})=3(\dfrac{27}{32})+\dfrac{171}{16}-\dfrac{45}{4}-28$

$q(\dfrac{3}{4})=\dfrac{81}{32}+\dfrac{171}{16}-\dfrac{45}{4}-28$

Taking LCM, we get

$q(\dfrac{3}{4})=\dfrac{81+342-360-896}{32}$

$q(\dfrac{3}{4})=\dfrac{-833}{32}\neq 0$

Since the value of the function at $\dfrac{3}{4}$ is not equal to 0, therefore, $\dfrac{3}{4}$ is not a root of the given function.

4 0

3 years ago

Find x when y=3 in the literal equation 3x+6y=24

pshichka [43]

When you plug in 3 in for y the equation is 3x + 6(3) = 24

3x + 18 = 24

subtract 18 from both sides

3x = 6

Isolate the x by dividing both side by 3

x = 2

4 0

4 years ago

Read 2 more answers

Please help me simplify these expressions

vaieri [72.5K]

Answer:

6p^5 q^3

Step-by-step explanation:

download the app cymath for these types of questions

this (^) means exponents

-----

Number 5:

2p^2qx3p^3q^2

Take out the constants (2x3)p^2p^3qq^2

Simplify 2x3 to 6, 6p^2p^3qq^2

6p^2+^3q^1+^2

simplify 2+3 to 5, 6p^5q^1+^2

simplify 1+2 to 3

6p^5 q^3

4 0

4 years ago

A lorry is travelling at 13.5 m/s along a stretch of road where the speed limit is 50 km/h. 1 kilometre = 1000metres 1 hour = 36

BabaBlast [244]

3600x13.5÷1000=48.6km/h

4 0

3 years ago

Please help me please!!!​

Please help me please!!!