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3 years ago

What must happen for historians to consider a particular time in a civilzation a classical period?

Mathematics

2 answers:

quester [9]3 years ago

7 0

Answer: D. The civilization must make extraordinary achievements in areas such as art and science

Ksivusya [100]3 years ago

5 0

The correct answer of the given question above would be option D. The thing that must happen for historians to consider a particular time in a civilization as a classical period is that, the civilization must make extraordinary achievements in areas such as art and science.

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Which equation represents a circle that contains the point (-5, 3) and has a center at (-2, 1)? Distance formula: vaa -02 (x - 1

natali 33 [55]

Given:

The center of the circle = (-2,1).

Circle passes through the point (-5,3).

To find:

The equation of the circle.

Solution:

Radius is the distance between the center of the circle and any point on the circle. So, radius of the circle is the distance between the points (-2,1) and (-5,3).

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$r=\sqrt{(-5-(-2))^2+(3-1)^2}$

$r=\sqrt{(-5+2)^2+(2)^2}$

$r=\sqrt{(-3)^2+(2)^2}$

On further simplification, we get

$r=\sqrt{9+4}$

$r=\sqrt{13}$

The standard form of a circle is:

$(x-h)^2+(y-k)^2=r^2$

Where, (h,k) is the center of the circle and r is the radius of the circle.

Substitute h=-2, k=1 and $r=\sqrt{13}$ .

$(x-(-2))^2+(y-1)^2=(\sqrt{13})^2$

$(x+2)^2+(y-1)^2=13$

Therefore, the equation of the circle is $(x+2)^2+(y-1)^2=13$ .

8 0

3 years ago

Suppose that is in standard position and the given point is on the terminal side of 0. Give the exact value of the indicated tri

Lilit [14]

Answer:

12/13

Step-by-step explanation:

The length of the segment from the origin to the terminal point is ...

r = √((-5)² +12²) = √169 = 13

The sine of the angle is the ratio of the y-coordinate to this distance

sin(θ) = y/r = 12/13

_____

Additional comment

The other trig functions are ...

cos(θ) = x/r = -5/13

tan(θ) = y/x = -12/5

This is a 2nd-quadrant angle, where the sine is positive, but the cosine and tangent are negative.

6 0

2 years ago

Can someone help me with this?

Oduvanchick [21]

Answer:

Equation

Step-by-step explanation:

Equation Rate of change: 2/1=2

Graph Rate of Change: -4/1=-4

8 0

3 years ago

Read 2 more answers

4x square+ 8 x - 5=0<br><img src="https://tex.z-dn.net/?f=4%20%7Bx%7D%5E%7B2%7D%20%20%2B%208x%20-%205%20%3D%200" id="TexFormula1

Damm [24]

Answer:

$x = \frac{1}{2}$

$x = -\frac{5}{2}$

Step-by-step explanation:

Solve Using the Quadratic Formula

4x^2 + 8x − 5 = 0

Use the quadratic formula to find the solutions.

−b ± √b^2 − 4 (ac)

-------------------------

Substitute the values a = 4, b = 8, and c = −5 into the quadratic formula and solve for x.

−8 ± √82 − 4 ⋅ (4 ⋅ −5)

-------------------------

2 ⋅ 4

Simplify the numerator.

Raise 8 to the p ower of 2.

−8 ± √64 − 4 ⋅ 4 ⋅ −5

x= ---------------------------

2 ⋅ 4

Multiply −4 by 4.

−8 ± √64 − 16 ⋅ −5

x = -------------------------

2 ⋅ 4

Multiply −16 by −5.

−8 ± √64 + 80

x = -------------------

2 ⋅ 4

Add 64 and 80.

−8 ± √144

x = --------------

2 ⋅ 4

Rewrite 144 as 12^2.

−8 ± √122

x = ------------

2 ⋅ 4

Pull terms out from under the radical, assuming positive real numbers.

multiply 2 by 4

−8 ± 12

x= ------------

simplify

−2 ± 3

x= ---------

The final answer is the combination of both solutions.

x= 1/2, -5/2

Hope this helped!

6 0

3 years ago

Read 2 more answers

How can I solve 2x+y=-3

Vladimir79 [104]

Answer:

If solving for x then x = -3/2 +y/2

If solving for y then y = -3-2x

Step-by-step explanation:

For x: Divide both sides by 2

For y: Subtract 2x from both sides of the equation

4 0

3 years ago