Answer:
Factor this polynomial:
F(x)=x^3-x^2-4x+4
Try to find the rational roots. If p/q is a root (p and q having no factors in common), then p must divide 4 and q must divide 1 (the coefficient of x^3).
The rational roots can thuis be +/1, +/2 and +/4. If you insert these values you find that the roots are at
x = 1, x = 2 and x = -2. This means that
x^3-x^2-4x+4 = A(x - 1)(x - 2)(x + 2)
A = 1, as you can see from equation the coefficient of x^3 on both sides.
Typo:
The rational roots can be
+/-1, +/-2 and +/-4
Step-by-step explanation:
An angle is denoted by the angle symbol ∠ and the three letters representing the name of the angle.
An angle is denoted by the angle symbol ∠ which is then being followed by three letters that will represent the points that form an angle.
Lets say for example, the expression ∠ABC will mean that “the angle is formed by the points A, B and C”
where the vertex of the angle is at the point B as it is in the middle.
Angles can also be of different types like:
An Acute Angle which means an angle is less than 90 degrees.
A Right Angle which means an angle which is exactly 90 degrees.
An Obtuse Angle which is an angle more than 90 degrees and less than 180 degrees.
A Straight Angle which is an angle that is exactly 180 degrees.
And a Reflex Angle which is an angle greater than 180 degrees and less than 360 degrees.
Therefore, an angle is denoted by the angle symbol ∠ and the three letters representing the name of the angle.
Learn more about angles here:
brainly.com/question/25716982
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The <span>given the piecewise function is :
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![f(x) = \[ \begin{cases} 2x & x \ \textless \ 1 \\ 5 & x=1 \\ x^2 & x\ \textgreater \ 1 \end{cases} \]](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5C%5B%20%5Cbegin%7Bcases%7D%20%0A%20%20%20%20%20%202x%20%26%20x%20%5C%20%5Ctextless%20%5C%20%201%20%5C%5C%0A%20%20%20%20%20%205%20%26%20x%3D1%20%5C%5C%0A%20%20%20%20%20%20x%5E2%20%26%20x%5C%20%5Ctextgreater%20%5C%201%20%0A%20%20%20%5Cend%7Bcases%7D%0A%5C%5D)
To find f(5) ⇒ substitute with x = 5 in the function → x²
∴ f(5) = 5² = 25
To find f(2) ⇒ substitute with x = 5 in the function → x²
∴ f(2) = 2² = 4
To find f(-2) ⇒ substitute with x = 5 in the function → 2x
∴ f(-2) = 2 * (-2) = -4
To find f(1) ⇒ substitute with x = 1 in the function → 5
∴ f(1) = 5
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So, the statements which are true:<span>

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I think the answer could possibly be a
1) combine like terms (k)
0 = 7k
k = 0/7 = 0
zero divided by any numbers will be zero
2) combine the like terms (the constant of -4 + 1)
9 = 6x - 3
add 3 to both sides
12 = 6x
x=2
3) -3+3=0
-4=v
4) 4+3=7
8=k+7
k=1
5)x-5x = -4x
16= -4x
x = -4