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3 years ago

Which of the following is a specific species designation

Mathematics

1 answer:

Nutka1998 [239]3 years ago

5 0

Sapien because the word homo in homo sapien is the genus name, while the word sapien is the species name.

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The distance, d, in kilometres, travelled by a plane after t hours can be represented by d(t)=-4t³=40t²+500t, where t is greater

Ede4ka [16]

D(t) = -4t^3 + 40t^2 + 500t = 4088
4t^3 - 40t^2 - 500t + 4088 = 0
t = 7

Therefore, the plane has flown 4088 km 7 hours after it took off.

8 0

3 years ago

There are 16 marbles in a bag 12 of them are blue and 4 are yellow. what is the probability of picking a blue marble then a yell

Art [367]

Answer:

1/5

Step-by-step explanation:

the prob that you will pick a blue marble would be 12/16, easy.

then the prob of picking a yellow marble after that would be 4/15 since one marble is already missing. multiply the numerator and denominator of each fraction. so 12 x 4 and 16 x 15 to get 48/240. then divide each by 48 to get 1/5.

3 0

2 years ago

376×74 help and show work

hoa [83]

Answer:

27,824

Step-by-step explanation:

i just calculated it.

3 0

3 years ago

Read 2 more answers

Kayla and latasha work for a department store the amount of sales they made over the last year was collected monthly in the data

tresset_1 [31]

Based on the information represented by the boxplot ;

Latasha's lowest sale amount = 50

Kayla's median is between 200 and 300

Latasha has a greater spread due to higher IQR value

1.) The Lowest amount of sale made by Latasha in one month

The minimum value is denoted by the starting position of the lower whisker on a boxplot.

Lowest amount of sale made by Latasha = 50

2.) 50% of sales made by Kayla :

50% of sales made marks the median value in a boxplot, it is denoted by the vertical line in between the box.

50% of sales made by Kayla is between 200 and 300

With median sale value being 250

3.) Spread of the middle 50% of sales :

The measure of spread of the middle 50% of a distribution on a boxplot is the Interquartile range (IQR) of the distribution

IQR = Upper Quartile (Q3) - Lower quartile(Q1)

For Latasha :

Q3 = 450 (Endpoint of the box)
Q1 = 150 (starting point of the box)

IQR = 450 - 150 = 300

For Kayla :

Q3 = 375 (Endpoint of the box)
Q1 = 100 (starting point of the box)
IQR = 375 - 100 = 275

Since, Latasha's IQR is greater than Kayla's, then Latasha has a greater mid 50% spread than Kayla.

Learn more :brainly.com/question/24582786

4 0

2 years ago

tim spends 25% of his time at the gym dooing leg exercises , 1/5 on shoulder exercises , 0.35 on biceps exercises , and warming

svetoff [14.1K]

Answer:

20%

Step-by-step explanation:

1/5 of 1 hour = 20 minutes

so 1/5 = 20%

25% + 20% = 45%

0.35 = 35%

45% + 35% = 80%

100% - 80% = 20%

Answer = 20%

Hope this helps!

3 0

3 years ago