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maw [93]
3 years ago
5

A pirate shoots a cannonball into the air from a height of 10

Mathematics
1 answer:
Aneli [31]3 years ago
6 0

We are basically given most of what we need to calculate the height of the cannonball.

We use the formula h = –16t+ vt + s to find the height requested.

Let v = 160

Let s = 10

Let t = time in seconds

Was the value of t included? We need to know t to plug into our formula.

You know everything else except for t. Go back to your notes to search for t. Afterward, plug the value of t and everything else given above into the formula and calculate to find h.

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Find the volume of a cylinder with a diameter if 10 cm and a height of 10 cm?​
RideAnS [48]

Step-by-step explanation:

volume of cylinder=π(d/2)²h=π/4×10²×10=250πcm³

7 0
2 years ago
Read 2 more answers
HELP PLEASE NEED IT
dem82 [27]

Answer:

256 degrees.

Step-by-step explanation:

The figure is a parallelogram so m < 1 = 180-52 = 128 degrees (same side angles).

Also m < 2 = m < 1  (opposite angles of a parallelogram), so their sum is 2*128

= 256 degrees.

6 0
3 years ago
What is the measure of the third angle?
SCORPION-xisa [38]
The total amount of degrees in a triangle is 180. All three angles should add up to 180˚

We know that 40+60 = 100

The next step is to do 180-100 to get the other angle.
180-100 = 80

So the measure of the third angle is 80˚

Hope this helps!

(Also if you want to do this in one equation, you would do 40+60+x = 180
40+60+x = 180
100+x = 180 (combine like terms)
x = 80 (Subtract 100 from both sides)
7 0
3 years ago
Divide the number 20 into two parts (not necessarily integers) in a way that makes the product of one part with the square of th
Ilya [14]

Answer:

13 1/3 and  6 2/3.

Step-by-step explanation:

Let the 2 parts be x and (20 - x).

So x^2(20 - x) must be a maximum.

y = x^2(20 - x)

y = 20x^2 - x^3

Finding the derivative):

y' =  40x - 3x^2 = 0   for  maxm/minm value.

x( 40 - 3x) = 0

40 - 3x = 0

3x = 40

x = 40/3.

This is a maximum because the second derivative y" =  40 - 6x = 40 - 6(40/3)) is negative.

So the 2 numbers are 13 1/3 and  6 2/3.

3 0
2 years ago
*20 POINTS*
Paraphin [41]

Answer:

If you want to use the Rational Zeros Theorem, as instructed, you need to use synthetic division to find zeros until you get a quadratic remainder.

P: ±1, ±2, ±3, ±6  (all prime factors of constant term)

Q: ±1, ±7              (all prime factors of the leading coefficient)

P/Q: ±1, ±2, ±3, ±6, ±1/7, ±2/7, ±3/7, ±6/7  (all possible values of P/Q)

Now, start testing your values of P/Q in your polynomial:

f(x)=7x4-9x3-41x2+13x+6

You can tell f(1) and f(-1) are not zeros since they're not = 0Now try f(2) and f(-2):

f(2)=7(16)-9(8)-41(4)+13(2)+6

       112-72-164+26+6 ≠ 0

f(-2)=7(16)-9(-8)-41(4)+13(-2)+6

       112+72-164-26+6 = 0  OK!! There is a zero at x=-2

This means (x+2) is a factor of the polynomial.

Now, do synthetic division to find the polynomial that results from

(7x4-9x3-41x2+13x+6)÷(x+2):

-2⊥ 7   -9   -41    13     6

         -14   46   -10    -6          

      7  -23   5       3     0     The remainder is 0, as expected

The quotient is a polynomial of degree 3:

7x3-23x2+5x+3

Now, continue testing the P/Q values with this new polynomial.  Try f(3):

f(3)=7(27)-23(9)+5(3)+3

      189-207+15+3 = 0  OK!!  we found another zero at x=3

Now, another synthetic division:

3⊥ 7   -23    5     3

          21   -6   -3_

    7    -2    -1    0  

The quotient is a quadratic polynomial:

7x2-2x-1  This is not factorable, you need to apply the quadratic formula to find the 3rd and 4th zeros:

x= (1±2√2)÷7

The polynomial has 4 zeros at x=-2, 3, (1±2√2)÷7

Step-by-step explanation:

7 0
3 years ago
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