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3 years ago

A volleyball uniform costs $13 for the shirt, $11 for pants, and $8 for socks. Write two

Mathematics

2 answers:

alexdok [17]3 years ago

5 0

13^12 + 11^12 + 8^12 = 384 It will cost 384 dollars for all 12 uniforms

Nat2105 [25]3 years ago

5 0

Answer:

$384

Step-by-step explanation:

Expression 1

$13*12 + $11*12 + $8*12 = $384

Expression 2

($13 + $11 + $8)*12 = $384

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Midpoint of the x intercepts of f(x)=(x-4)(x+4)

lorasvet [3.4K]

The x-intercept is defined to be the value of x when y is zero. Based on the graph of the function: f(x) = (x-4)(x+4), the x-intercepts are located at (-4, 0) and (4,0). At these points the graph intersects the x-axis. The midpoint of the x-intercepts is located at the middle of the two points. In this case, the graph shows that it is at the origin or at (0,0).

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2 years ago

Read 2 more answers

A kitchen sink faucet streams 0.5 gallon of water in 10 seconds. A bathroom sink faucet stream 0.75 gallon of water in 18 second

Masteriza [31]

Answer:

kitchen sink faucet stream

Step-by-step explanation:

with kitchen sink faucet you fill 0.05gallons of water per second you get that by dividing 0.5 by 10

and the bathroom sink faucet does 0.041gallons of water per second you get that by dividing 0.75 by 18

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3 years ago

Evaluate: 6-(2/3)^2 A. 17/3 B. 52/3 C. 49/9 D. 50/9

Komok [63]

Answer:

The correct answer is: "Option [D]".

Step-by-step explanation:

Hi student, let me help you out!

....................................................................................................................................

Let's use the acronym PEMDAS. With the help of this little acronym, we will not make mistakes in the Order of Operations! :)

$\dag\textsf{Acronym \: PEMDAS}$

P=Parentheses,

E=Exponents,

M=Multiplication,

D=Division,

A=Addition,

S=Subtraction.

Now let's start evaluating our expression, which is $\mathsf{6-(\cfrac{2}{3})^2}$

According to PEMDAS, the operation that we should perform is "E-Exponents".

Notice that we have a fraction raised to a power. When this happens, we raise both the numerator (2 in this case) and the denominator (3 in this case) to that power, which is 2. After this we obtain $\mathsf{6-\cfrac{4}{9}}$ .

See, we raised both the numerator and the denominator to the power of 2.

Now what we should do is subtract fractions.

Note that 6 and -4/9 have unlike denominators. First, let's write 6 as a fraction: $\mathrm{\cfrac{6}{1}-\cfrac{4}{9}}$ . Now let's multiply the denominator and the numerator of the first fraction times 9: $\mathrm{\cfrac{54}{9}-\cfrac{4}{9}}$ .

See, now the fractions have the same denominator. All we should do now is subtract the numerators: $\mathrm{\cfrac{50}{9}}$ .