Answer:
V1 = 60 km/h
V2 = 40 Km/h
Step-by-step explanation:
The speed of an object is defined as
Speed = distance / time
Let
V1 be the speed of the faster car
V2 be the speed of the other car
t1 the time it took for the first car to arrive
t2 the time it took for the second car to arrive
d1 the distance traveled by first car
d2 the distance traveled by second car
We know thanks to the problem that
V1 = V2 + 20 Km/h
t1 = t2 - 1 hour
d1 = d2 = 120 Km
d1 = V1 * t1
d2 = V2* t2
V1 * t1 = V2* t2
V1* t1 = (V1 -20)*(t1 +1)
The system of equations
(V1 -20)*(t1 +1) = 120
V1 * t1 = 120
120 + (120/t1) -20*t1 = 140
(120/t1) -20*t1 = 20
Which gives,
t1 = 2
This means
V1 = 60 km/h
V2 = V1 - 20 Km/h = 40 Km/h
Answer:
1: n > -75
2: n < -12
Step-by-step explanation:
1: n/-3 - 8 < 17
n/-3 (- 8 + 8) < 17 + 8
n/-3 < 25
n/-3(-3) < 25(-3)
n < -75
n > -75 (switch symbol when you divide or multiply by a negative number)
2: n/-2 + 11 > 17
n/-2 (+ 11 - 11) > 17 - 11
n/-2 > 6
n/-2(-2) > 6(-2)
n > -12
n < -12 (switch symbol when you divide or multiply by a negative number)
Description:
This will be no solution because when we add 10 to both sides of the equation then simplify it. After that we will subtract 6 from both sides. It will give us no solution. For more info please see the attachment.
Answer: No solution
Hope this helps.
