The sequence forms a Geometric sequence as the rule to obtain the value for the next term is by ratio
Term 1: 1000
Term 2: 200
Term 3: 40
From term 1 to term 2, there's a decrease by

From term 2 to term 3, there's a decrease also by

The rule to find the

term in a sequence is

, where

is the first term in the sequence and

is the ratio
So, the formula for the sequence in question is

term =

The sequence is a divergent one. We can always find the value of the next term by dividing the previous term by 5 and if we do that, the value of the next term will get closer to 'zero' but never actually equal to zero.
We can find a partial sum of the sequence using the formula

for -1<r<1
Substituting

and

we have

=

= 1250
Hence, the correct option is option number 1
By substitution,



and so on, so that
[tex]g(n)=6.1^{n-1}g(1)=2.7\cdot6.1^{n-1}
Answer:
x = 1 Whole 1/3
Step-by-step explanation:
10001010100110010101001010101010111000100101010