Answer:
Step-by-step explanation:
set the two equations equal to each other then solve for n
6n + 3 = 4n + 11
2n = 8
n = 4
plug n in for both equations
6(4) + 3
24 + 3 = 27
4(4) + 11
16 + 11 = 27
27 + 27 = 54
the distance is 54
Answer:
The nth term in the sequence is given by the equation:

Step-by-step explanation:
Arranging a table for n and nth:
![\left[\begin{array}{ccc}n&nth\\1&1\\2&3\\2&16\\4&125\\5&1296\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dn%26nth%5C%5C1%261%5C%5C2%263%5C%5C2%2616%5C%5C4%26125%5C%5C5%261296%5Cend%7Barray%7D%5Cright%5D)
It is easier to notice that 16 and 125 result from the second power of 4 and the third of 5, respectively, which are one number below their respective position. That is why we can deduce that the base of the power is n+1.
For n=2, the base n+1 results in 3, which matches the nth term for n=2. Since 3 is the result of 3 to the power of 1, 16 is 4 to the power of 2, and 125 is 5 to the power of 3, all the powers are one number behind n, so the power is given by n-1, giving the equation:

Answer:
fifth oeriod and jeffersons road
Step-by-step explanation:
because on the first the average is higher and on the second the mean (quadrent 2) is fartheralong than the other road and although the other has an outlier it isnt strong enough to skew the data to being higher
Answer:
A) mPQ = 71º
B) mSR = 161º
C) mQRT = 199ª
D) mPSR = 270º
E) mPS = 109º
Step-by-step explanation:
We know that mST is 19º and QR is also 19º because they're opposite angles. We also know that angle PUR is 90º.
If we subtract 19º from 90º we get 71º for mPQ.
We also know that TR is a 180º angle. Using this if we take 19º from 180º we're left with 161º for mSR.
Using the 180º from angle TR, as well as the 19º from mQR we know that mQRT has to be 199º.
A circle is 360º and a right angle is 90º. That means that mPSR is 270º.
Knowing that TR is 180º and that PR is 90º, PTº must be supplementary making it also 90º. Adding the 19º from ST to the 90º from TP we know that PS is 109º
Answer:
Domain? Do you by chance mean quadrant? If so it's the 3rd quadrant.
Step-by-step explanation:
In the future try to imagine quadrant 1 in the top right and then going counter-clockwise! It'll help!