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mezya [45]
3 years ago
15

Solve for x.

Mathematics
2 answers:
kipiarov [429]3 years ago
6 0
X=-3 is the right answer
AURORKA [14]3 years ago
6 0

Answer:

this isss itttt. You're welcome

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An investment broker puts 1/12 of his paycheck into a retirement account every quarter? How much of his $84,000 salary is put in
posledela

Answer:

<u>$7000</u> of his salary is put into this account each quarter.

Step-by-step explanation:

Given:

An investment broker puts 1/12 of his paycheck into a retirement account every quarter.

His salary is $84,000.

Now, to find how much is put into this account each quarter.

As given salary = $84,000.

So, amount to put into this account every quarter =

\frac{1}{12} of\ \$84,000.

=\frac{1}{12} \times 84000

=\frac{84000}{12}

=\$7000.

Therefore, $7000 of his salary is put into this account each quarter.

6 0
3 years ago
Find the distance between the point (3,1) and the line with the equation y=2x-5
True [87]

Answer:

B:  0

Step-by-step explanation:

Note that (3, 1) satisfies the equation y = 2x - 5:

1 = 2(3) - 5

1  =  6 -5  = 1

Therefore, the distance between this point and this line is zero.

B is the correct answer.

3 0
3 years ago
NASA launches a rocket at t = 0 seconds. Its height, in meters above sea-level, as a function of time is given by h ( t ) = − 4.
Oliga [24]

Answer:

\displaystyle 1)48.2    \:  \: \text{sec}

\rm \displaystyle  2)3021.6 \: m

Step-by-step explanation:

<h3>Question-1:</h3>

so when <u>flash down</u><u> </u>occurs the rocket will be in the ground in other words the elevation(height) from ground level will be 0 therefore,

to figure out the time of flash down we can set h(t) to 0 by doing so we obtain:

\displaystyle  - 4.9 {t}^{2}  + 229t + 346 = 0

to solve the equation can consider the quadratic formula given by

\displaystyle x =  \frac{ - b \pm  \sqrt{ {b}^{2} - 4 ac} }{2a}

so let our a,b and c be -4.9,229 and 346 Thus substitute:

\rm\displaystyle t =  \frac{ - (229) \pm  \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}

remove parentheses:

\rm\displaystyle t =  \frac{ - 229 \pm  \sqrt{ {229}^{2} - 4.( - 4.9)(346)} }{2.( - 4.9)}

simplify square:

\rm\displaystyle t =  \frac{ - 229 \pm  \sqrt{ 52441- 4( - 4.9)(346)} }{2.( - 4.9)}

simplify multiplication:

\rm\displaystyle t =  \frac{ - 229 \pm  \sqrt{ 52441- 6781.6} }{ - 9.8}

simplify Substraction:

\rm\displaystyle t =  \frac{ - 229 \pm  \sqrt{ 45659.4} }{ - 9.8}

by simplifying we acquire:

\displaystyle t = 48.2  \:  \:  \: \text{and} \quad  - 1.5

since time can't be negative

\displaystyle t = 48.2

hence,

at <u>4</u><u>8</u><u>.</u><u>2</u><u> </u>seconds splashdown occurs

<h3>Question-2:</h3>

to figure out the maximum height we have to figure out the maximum Time first in that case the following formula can be considered

\displaystyle x _{  \text{max}} =  \frac{ - b}{2a}

let a and b be -4.9 and 229 respectively thus substitute:

\displaystyle t _{  \text{max}} =  \frac{ - 229}{2( - 4.9)}

simplify which yields:

\displaystyle t _{  \text{max}} =  23.4

now plug in the maximum t to the function:

\rm \displaystyle  h(23.4)- 4.9 {(23.4)}^{2}  + 229(23.4)+ 346

simplify:

\rm \displaystyle  h(23.4)  =  3021.6

hence,

about <u>3</u><u>0</u><u>2</u><u>1</u><u>.</u><u>6</u><u> </u>meters high above sea-level the rocket gets at its peak?

5 0
2 years ago
How do I figure this anser-6w &lt; 84​
Sophie [7]

Answer:

w > -14

Step-by-step explanation:

Divide both sides by -6.

-6w/-6 = w

84/-6 = 14

Since it's an equality, if the coefficient of the variable is negative, when you divide the sign flips to the opposite.

4 0
3 years ago
Triangles J K L and X Y Z are shown. Angles K J L and Y X Z are right angles. The length of Y X is 10. The length of hypotenuse
pickupchik [31]

ΔJKL and ΔXYZ CANNOT be congruent triangles because: the hypotenuse of one triangle is equal in length to the leg of the other triangle.

<h3>What are Congruent Triangles?</h3>

Congruent triangles are triangles whose corresponding sides are congruent to each other.

The hypotenuse of triangle JKL(KL = 10) is congruent to a leg of triangle XYZ (YX = 10). This implies that they cannot be congruent triangles.

Therefore, ΔJKL and ΔXYZ CANNOT be congruent triangles because: the hypotenuse of one triangle is equal in length to the leg of the other triangle.

Learn more about congruent triangles on:

brainly.com/question/11457412

3 0
1 year ago
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