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Ugo [173]
3 years ago
8

Kinley bought 3 notebooks that cost the same and a poster that cost $6. She spent $20.40 in all. What was the cost of each noteb

ook?
Mathematics
1 answer:
kirza4 [7]3 years ago
8 0

Answer:

the cost of each notebook is $4.8

Step-by-step explanation:

Cost of each notebook= ?

Cost of a poster = $6

Total amount she spent = $20.40

If we subtract the cost of poster from total amount we get the cost of 3 notebooks.

$20.40-$6

=$ 14.4

It means the cost of 3 notebooks = $14.4

To find the cost of each notebook divide the cost of 3 notebooks by the number of books.

=14.4/3

=$4.8

Thus the cost of each notebook is $4.8....

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There would be 21 adults on the bus.

7:5

21:15

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The canopy of a parachute is a semicircle with a radius of 13 feet. A company that is making parachutes for a Fourth of July cel
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88.5 ft sq

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4 years ago
Cos(100)-cos(99)=?<br> Can you do it step by step
Svetllana [295]

Let's see what to do buddy...

________________________________

<em><u>If</u></em><em> </em><em>9</em><em>9</em><em> </em><em>&</em><em> </em><em>1</em><em>0</em><em>0</em><em> </em><em>are</em><em> </em><em>in</em><em> </em><em>D</em><em>eg</em><em>ree</em>

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STEP (1)

The angles 99 and 100 are in the second quarter of the trigonometric circle.

The cosine is negative in the second quarter.

To make things easier, we can use angle conversion.

Look :

we \: know \: that \: 100 = 90 + 10

also \: we \: know \: 99 = 90 + 9

So :

\cos(100) =  \cos(90 + 10) =  \cos( \frac{\pi}{2} + 10 )  \\

\cos(99) =  \cos(90 + 9) =  \cos( \frac{\pi}{2} + 9 ) \\

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STEP (2)

Well now we have to do the arc deletion.

To remove the arc, we remove π/2 from the arc.

Remember that every time we remove π/2 from the arc, the trigonometric ratio changes.

That is, if it is a sine, it becomes a cosine, and if it is a cosine, it becomes a sine.

Or if it is a tangent, it becomes a cotangent, and if it is a cotangent, it becomes a tangent.

in \: second \: quarter \: cosine \: is \: negative \\ \\  \cos( \frac{\pi}{2} + 10 ) =  -  \sin(10) =  - 0.173

\cos( \frac{\pi}{2} + 9 ) =  -  \sin(9)  =  - 0.156 \\

_________________________________

STEP (3)

\cos(100) -  \cos(99) =  \\  -  \sin(10)  - ( -  \sin(9) \: ) =  \\  - 0.173 - ( - 0.156) =  \\  - 0.173 + 0.156 =  - 0.017

And we're done here.

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<em>If</em><em> </em><em>9</em><em>9</em><em> </em><em>&</em><em> </em><em>1</em><em>0</em><em>0</em><em> </em><em>are</em><em> </em><em>in</em><em> </em><em>Radia</em><em>n</em>

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STEP (1)

First we need to know how many degrees 1 radian is.

The following equation is used to convert degrees to radians or radians to degrees.

\frac{degree}{180} =  \frac{radian}{\pi} \\

So we have :

\frac{d}{180} =  \frac{1}{\pi} \\

Multiply the sides of the equation by 180 :

d =  \frac{180}{\pi} =  \frac{180}{3.14} = 57.32 \\

So 1 radian is approximately equal to 57 degrees.

And we have :

100 \: rad \:  = 100 \times 57 = 5700 \: deg \\  \\ 99 \: rad \:  = 99 \times 57 = 5601 \: deg

_________________________________

STEP (2)

Let's move on to deletion.

Look : 5700° = 15 × 360° + 300°

and : 5601° = 15 × 360° + 201°

We know π rad = 3.14 × 57 = 180° deg

So 2π rad = 2 × 180 = 360 ° deg

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and :5601 = 15 × 2 π + 201° = 30 π + 201°

Remember that deleting 2π is unconditional.

\cos(30\pi + 300) =  \cos(300) =  \cos(360 - 60) =  \cos(2\pi - 60) =  \cos( - 60) =  \\ cosine \: eat \: negative \\  \cos( - 60) =  \cos(60) =  \frac{1}{2}

\cos(30\pi  +  201) =  \cos(201) = \\  \cos(180 + 21) =  \cos(\pi + 21) = \\  -  \cos(21) =  - 0.933

\frac{1}{2} - ( - 0.933) = 0.500 + 0.933 = 1.433

And we're done.

Thanks for watching buddy good luck.

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