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4 years ago

What fraction is equivalent to 274/399

Mathematics

1 answer:

liberstina [14]4 years ago

3 0

Answer: 548/798

Explanation: You can multiply both the numerator and denominator by 2 or a bigger number to get a fraction equal to 274/399

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Essential: Solve the proportions step by step

vazorg [7]

Answer:

The value of r= $\frac{-106}{47}$

The value of x= $\frac{83}{32}$

Step-by-step explanation:

Given that,

A) $\frac{2r-2}{7r+10} = \frac{9}{8}$

Now,

$\frac{2r-2}{7r+10} = \frac{9}{8}$

8(2r-2)=9(7r+10)

16r-16=63r+90

-16-90=63r-16r

-(16+90)=47r

-106=47r

r= $\frac{-106}{47}$

B) $\frac{x+4}{9} = \frac{3(x-2)-1}{5}$

Now,

$\frac{x+4}{9} = \frac{3(x-2)-1}{5}$

5(x+5)=9[3(x-2)-1]

5x+25=9[3x-6-1]

5x+25=9[3x-7]

5x+25=27x-63

25+63=27x+5x

83=32x

x= $\frac{83}{32}$

6 0

4 years ago

A sled is being held at rest on a slope that makes an angle theta with the horizontal. After the sled is released, it slides a d

Alenkasestr [34]

Answer:

μ = Sin θ * d₁ / (d₂ - Cos θ*d₁)

d₂ = (d₁*Sin θ) / μ

Step-by-step explanation:

a) We apply The work-energy theorem

W = ΔE

W = - Ff*d

Ff = μ*N = μ*m*g

Distance 1:

- Ff*d₁ = Ef - Ei

⇒ - (μ*m*g*Cos θ)*d₁ = (Kf+Uf) - (Ki+Ui) = (Kf+0) - (0+Ui) = Kf - Ui

Kf = 0.5*m*vf² = 0.5*m*v²

Ui = m*g*h = m*g*d₁*Sin θ

then

- (μ*m*g*Cos θ)*d₁ = 0.5*m*v² - m*g*d₁*Sin θ

⇒ - μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ (I)

Distance 2:

- Ff*d₂ = Ef - Ei

⇒ - (μ*m*g)*d₂ = (0+0) - (Ki+0) = - Ki

Ki = 0.5*m*vi² = 0.5*m*v²

then

- (μ*m*g)*d₂ = - 0.5*m*v²

⇒ μ*g*d₂ = 0.5*v² (II)

If we apply (I) + (II)

- μ*g*Cos θ*d₁ = 0.5*v² - g*d₁*Sin θ

μ*g*d₂ = 0.5*v²

⇒ μ*g (d₂ - Cos θ*d₁) = v² - g*d₁*Sin θ (III)

Applying the equation (for the distance 1) we get v:

vf² = vi² + 2*a*d = 0² + 2*(g*Sin θ)*d₁ ⇒ vf² = 2*g*Sin θ*d₁ = v²

then (from the equation III) we get

μ*g (d₂ - Cos θ*d₁) = 2*g*Sin θ*d₁ - g*d₁*Sin θ

⇒ μ (d₂ - Cos θ*d₁) = Sin θ * d₁

⇒ μ = Sin θ * d₁ / (d₂ - Cos θ*d₁)

If μ is a known value

d₂ = ?

We apply The work-energy theorem again

W = ΔK ⇒ - Ff*d₂ = Kf - Ki

Ff = μ*m*g

Kf = 0

Ki = 0.5*m*v² = 0.5*m*2*g*Sin θ*d₁ = m*g*Sin θ*d₁

Finally

- μ*m*g*d₂ = 0 - m*g*Sin θ*d₁ ⇒ d₂ = Sin θ*d₁ / μ

3 0

4 years ago

Is the m in mx+b=y the growth

Shalnov [3]

The "m" in y = mx + b is the slope.

It is the number of units a point goes up, down, left, or right each time. Making the line linear/straight.

$m = \frac{rise}{run}$

"rise" is the the number of units you go up(+) or down(-), "run" is the number of units you go to the right

For example, if your slope is:

$\frac{1}{2}$

You are going up 1 unit, and to the right 2 units

3 or $\frac{3}{1}$

You are going up 3 units, and to the right 1 unit

$-\frac{1}{2}$

You are going down one unit, and to the right 2 units

-3 or $-\frac{3}{1}$

You are going down 3 units, and to the right 1 unit

4 0

3 years ago

Read 2 more answers

WILL MARK BRAINLIEST!!!

patriot [66]

Answer:

option D.

Step-by-step explanation:

average rate of change in steel production over the eight days=-0.15 tons per day

Step-by-step explanation:

The production rate of a steel factory is declining due to old machinery. Over the last eight days production has dropped by 1.2 tons.

Production is dropped by 1.2 tons, so its negative

Average rate of change = Change in production / number of days

Average rate of change = -1.2/ 8= -0.15

so sorry -0.15

6 0

3 years ago

Question 4 of 11

MAVERICK [17]

This would be A True, hope this helps !

7 0

3 years ago