Answer:
<em>y = - </em>
<em> x - 7 </em>
Step-by-step explanation:
A( 
, 
) , B( 
, 
)
y - = m( x - )
m = 
~~~~~~~~~~~~~
( - 6, - 3 )
( - 3, - 5 )
m = 
= -
y + 5 = - ( x + 3)
y + 5 = - x - 2
<em>y = - </em><em> x - 7</em>
So 4 times 4 is 16 so the 1/4 is now 4/16 plus the 7/16 equals 11/16 so the left number is 5/16
Answer:
The real roots are
and 
The sum of the squares of these roots is 
Step-by-step explanation:
The given quadratic equation is 
has two real roots.
To find the roots .
Dividing the above equation by 2
For quadratic equation 
the solution is 
Where a and b are coefficents of 
and x respectively, c is a constant.
For given quadratic equation
a=4, b=6, c=-7
The real roots are
and
Now to find the sum of the squares of these roots
![\left[\frac{-3+\sqrt{37}}{4}+\frac{(-3-\sqrt{37})}{4}\right]^2=\frac{-3+\sqrt{37}-3-\sqrt{37}}{4}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7B-3%2B%5Csqrt%7B37%7D%7D%7B4%7D%2B%5Cfrac%7B%28-3-%5Csqrt%7B37%7D%29%7D%7B4%7D%5Cright%5D%5E2%3D%5Cfrac%7B-3%2B%5Csqrt%7B37%7D-3-%5Csqrt%7B37%7D%7D%7B4%7D)
![\left[\frac{-3+\sqrt{37}}{4}+\frac{(-3-\sqrt{37})}{4}\right]^2=\frac{-3}{2}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7B-3%2B%5Csqrt%7B37%7D%7D%7B4%7D%2B%5Cfrac%7B%28-3-%5Csqrt%7B37%7D%29%7D%7B4%7D%5Cright%5D%5E2%3D%5Cfrac%7B-3%7D%7B2%7D)
Therefore the sum of the squares of these roots is
Check the picture below
hmmm so, notice the arrows, if we simply multiply top and bottom of one fraction by the other's denominator, we end up with two fractions, with the same denominator
now, what can be between 49/56 and 24/56
well, 25/56, or 26/56 or 48/56 or 39/56 and so on
once the denominators are the same, is just a matter of which numerator is larger or smaller, to see who is who
Answer:
[0,∞) {y║y≥0}
Step-by-step explanation:
The absolute value expression has a V shape. The range of a positive absolute value expression starts at its vertex and extends to infinity.
