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xxTIMURxx [149]
3 years ago
11

A particle whose mass is 4 kg moves in xyplane with a constant speed of 2 m/s in the positive x-direction along y = 6 m. Find th

e magnitude of its angular momentum relative to the point (x0, y0), where x0 = 0.9 m and y0 = 10 m. Answer in units of kg m2 /s.
Mathematics
1 answer:
s2008m [1.1K]3 years ago
5 0

Answer: 32.8kgm^2/s

Step-by-step explanation:

1. Angular momentum is a product of linear momentum and the distance of the object from a rotation axis.

2. Linear momentum (L) is given as :

L = mv

Where: m= mass = 4kg

v= velocity= 2m/s

=> L = 8kgm/s

Angular momentum (A) = L x centre distance (d) of object from a rotation axis

d = √(0.9-0)^2 + (10-6)^2 = 4.1m

=> A = 8 x 4.1 = 32.8kgm^2/s.

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AlladinOne [14]
(a) 95 = (x+7)*(x-7)

(b) 95 = (x+7)*(x-7) 
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7 0
3 years ago
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3 years ago
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Aleksandr [31]
= 7 2/5 - 1 4/5

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Hope this helps!
3 0
3 years ago
Read 2 more answers
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