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4 years ago

Enter the degree of the polynomial below 7x7+10x4+4x3-5x11-10x6-6x7

1 answer:

4 0

When there is only one variable, the degree is the highest exponent.

Degrees of each term from L to R: 7, 4, 3, 11, 6, 7

The biggest of these is 11.

Final answer: 11

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Margin of error and the confidence interval. A study of stress on the campus of your university reported a mean stress level of

victus00 [196]

Answer:

(a) The 95% confidence interval for the population mean stress level is (73, 83).

(b) Increasing the confidence level to 99% from 95% the margin of error would be greater than 5.

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for population mean is:

$CI=\bar x\pm MOE$

The information provided is:

$\bar x$ = 78

Confidence level = 95%

MOE = 5

(a)

Compute the 95% confidence interval for the population mean stress level as follows:

$CI=\bar x\pm MOE\\=78\pm5\\=(73, 83)$

Thus, the 95% confidence interval for the population mean stress level is (73, 83).

(b)

The formula to compute the margin of error (MOE) is:

$MOE=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

The margin of error is affected by:

Standard deviation
Sample size
Confidence level.

On increasing the confidence level the critical value of <em>z</em> increases.

$z_{90\%}=1.645\\z_{95\%}=1.96\\z_{99\%}=2.58$

And if the critical value is increased then the margin of error will also increase.

Thus, increasing the confidence level to 99% from 95% the margin of error would be greater than 5.

3 0

3 years ago

What's 676 divided by 13 in long division? I need step by step cause you have to drag the numbers.

Galina-37 [17]

Answer: 52

Step-by-step explanation: Not much work with this one but hope this helps :)

3 0

3 years ago

I think it's B, but idk, pls help

ale4655 [162]

(N+18)+2n=90
3n=90-18
3n=72
N=24
Yeah it’s b, you’re correct

3 0

4 years ago

Read 2 more answers

How do you write 1.12 × 103 in standard form?

QveST [7]

Answer:

115.36

Step-by-step explanation:

6 0

3 years ago

The manufacturer's suggested retail price (MSRP) for a particular car is $25,425, and it is expected to be

arsen [322]

Answer:

(a) The linear depreciation function of the car which gives the worth of the car y after a number of years, t is given as follows;

y = 25,425 - 2,739 × t

(b) The value of the car 7 years from now is $6,252

Step-by-step explanation:

The manufacture's suggested retail price (MSRP) for the car = $25,425

The amount the car is expected to be worth in 5 years = $11,730

(a) The linear depreciation is given as follows;

$Depreciation \ Per \ Year \ = \dfrac{Cost \ of \, Asset - Salvage \ Value}{Life \ of \, Asset \ in \ use}$

Where;

Cost of Asset = $25,425

Salvage Value = $11,730

Life of Asset in use = 5 years

We get;

$Depreciation \ Per \ Year \ = \dfrac{\$ 25,425 - \$11,730}{5} = \$2,739/year$

Therefore, the linear depreciation function, can be written as follows;

y - 25,425 = -2,739×(t - 0)

y = -2,739·t + 0 + 25,425 = 25,425 -2,739·t

y = 25,425 - 2,739 × t

Where;

y = The expected worth of the car after a given number of years

t = The number of years used for the calculation of the depreciation

(b) The value of the car 7 years from now is given by substitution as follows;

Whet t = 7, we have;

y = 25,425 -2,739·t = y = 25,425 -2,739 × 7 = $6,252

The value of the car 7 years from now = $6,252

The car is depreciating at a rate of $2,739 per year.

3 0

3 years ago