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Yuliya22 [10]
3 years ago
10

Enter the degree of the polynomial below 7x7+10x4+4x3-5x11-10x6-6x7

Mathematics
1 answer:
natta225 [31]3 years ago
4 0
When there is only one variable, the degree is the highest exponent.

Degrees of each term from L to R: 7, 4, 3, 11, 6, 7

The biggest of these is 11.

Final answer: 11
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How many tenths are there in 4/5
il63 [147K]
What we have to solve is:

\frac{4}{5} = \frac{x}{10}

we should multiply both sides by10, to get the "x" by itself:

\frac{4*10}{5} = \frac{x}



\frac{4*2}{1} = \frac{x}


8 = \frac{x}
 so there are 8 tenths in this number!

5 0
3 years ago
For a saturday matinee, adult tickets cost $5.50 and kids under 12 pay only $4.00. if 60 tickets are sold for a total of $285. h
podryga [215]
30 tickets for the kids and 30 for the adult
3 0
3 years ago
Manuel hizo un viaje en el coche, en el cual consumió 20 litros de gasolina. El trayecto lo hizo en dos partes: en la primera, c
Alona [7]

Responder:

24 litros; 16 litros; 4 litros

Explicación paso a paso:

Dado que:

Gasolina consumida = 20 litros

Sea la cantidad de gasolina en el tanque = x

Primera parte del viaje = 2/3 de x

Segunda parte del viaje = 1/2 de (x - 2x / 3)

Cantidad de gasolina en el tanque:

2x / 3 + 1/2 (x - 2x / 3) = 20

Solución para x

2x / 3 + x / 2 - x / 3 = 20

(4x + 3x - 2x) / 6 = 20

5 veces / 6 = 20

5 veces = 20 * 6

5 veces = 120

x = 120/5

x = 24

Cantidad de gasolina en el tanque = 24 litros

Litros consumidos en cada etapa:

Primera parte = 2/3 de 24 = 48/3 = 16 litros

2a parte = 0.5 de (24 - 16) = 0.5 * 8 = 4 litros

3 0
3 years ago
Use the distributive property to fill in the blanks below.
elena-14-01-66 [18.8K]

Answer:

(5×7)-(5×6) = 5×(7-6)

5 0
3 years ago
Will someone help with this ! I was allowed a retry for it and I don’t know how to do it
pashok25 [27]

Answer:

\frac{dN}{dt}=k(725-N)\\separating the variables and integrating\\\int \frac{dN}{725-N}=\int kdt+c\\-log (725-N)=kt+c\\log (725-N)=-kt-c\\(725-N)=e^{-kt-c} =e^{-kt} *e^{-c} =Ce^{-kt} \\when t=0,N=400\\725-400=Ce^{0} =C\\C=325\\when t=3,N=650\\725-650=325e^{-3k} \\\frac{75}{325}=(e^{-k})^3\\\\e^{-k} =(\frac{3}{13}) ^{\frac{1}{3} } \\when t=5\\725-N=325(\frac{3}{13}) ^{\frac{5}{3} } =325*\frac{3}{13}*(\frac{3}{13} )^{\frac{2}{3}}\\N=725-75*(\frac{3}{13} )^{\frac{2}{3} }=725-28=697

Step-by-step explanation:

6 0
3 years ago
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