Answer:
False
Step-by-step explanation:
If you do a = 6, then you get 6 > 6 which is not true. 6 isn't greater than itself.
Answer:
Therefore the function that models the height of the object after t seconds is given by "H(t) = 15 + 8.5*t + 16.09*t²".
Step-by-step explanation:
Since the object has a initial velocity and it's being accelerated by gravity, than it's height is defined by:
H(t) = H(0) + V(0)*t + 0.5*g*t²
Applying the data from the problem, we have:
H(t) = 15 + 8.5*t + 0.5*32.17405*t²
H(t) = 15 + 8.5*t + 16.09*t²
Therefore the function that models the height of the object after t seconds is given by "H(t) = 15 + 8.5*t + 16.09*t²".
Given:
The point (9,-12) is on terminal side of angle theta in standard position.
To find:
The exact value of each of the six trigonometric functions of theta.
Solution:
The given point is (9,-12). Here, x-coordinate is positive and y-coordinate is negative. So, the point lies in 4th quadrant and only cos and sec are positive in 4th quadrant.
We know that,
Now,
Therefore, the values of six trigonometric functions of theta are 
.
G(x) is irrelevant in this so cross that out. First it's asking for f(4) so plug in 4 to the f(x) equation *f(x)= 4^2+1 = 17. then you square 17 so 17^2 is 289
I don’t understand the question can you give more detail
