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tester [92]
3 years ago
7

Patrick has $12,000 saved for medical school from gifts and summer jobs. Because the cost of college has risen each year, Patric

k knows he needs a savings account that will help him meet these increases. In the 10 remaining years before he receives his medical degree, which of the following would most help Patrick to meet these increases?
A. A checking account
B. A compound interest account
C. A high risk investment
D. A simple interest account

Mathematics
1 answer:
mote1985 [20]3 years ago
3 0
D. A simple interest account
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Sara ordered 2 slices of pizza and a 12-ounce cola and paid
Natasha_Volkova [10]

Answer: a slice of pizza cost $1.25 and a 12-ounce cola cost $0.50.

Step-by-step explanation:

Let slice of pizza cost x and a 12-ounce cola cost y.

Then Sara's order cost: 2x+y=3

and Sydney's order cost: 3x+2y=4.75

From the first equation we have: y=3-2x and put this to the second equation:

3x+2(3-2x)=4.75

3x+6-4x=4.75

x=1.25

y=3-1.25*2=0.50

Answer: a slice of pizza cost $1.25 and a 12-ounce cola cost $0.50.

5 0
3 years ago
Can somebody please help with this?
sertanlavr [38]
(3, 62)


Since that second equation is equal to y, you can substitute the entire thing into the top equation, getting rid of the y and solving for x. It equals 3.

You can then plug 3 in for x on either equation, which should be 62.
6 0
3 years ago
In an experiment, a fair coin is tossed 13 times and the face that appears (H for head or T for tail) for each toss is recorded.
zalisa [80]

Answer:

1) 1 element

2) 13 elements

3) 22 elements

4) 40 elements

Step-by-step explanation:

1) Only one element will have no tails: the event that all the coins are heads.

2) 13 elements will have exactly one tile. Basically you have one element in each position that you can put a tail in.

3) There are {13 \choose 2} = 78 elements that have exactly 2 tails. From those elements we have to remove the only element that starts and ends with a tail and in the middle it has heads only and the elements that starts and ends with a head and in the 11 remaining coins there are exactly 2 tails. For the last case, there are {11 \choose 2} = 55 possibilities, thus, the total amount of elements with one tile in the border and another one in the middle is 78-55-1 = 22

4) We can have:

  • A pair at the start/end and another tail in the middle (this includes a triple at the start/end)
  • One tail at the start/end and a pair in the middle (with heads next to the tail at the start/end)

For the first possibility there are 2 * 11 = 22 possibilities (first decide if the pair starts or ends and then select the remaining tail)

For the second possibility, we have 2*9 = 18 possibilities (first, select if there is a tail at the end or at the start, then put a head next to it and on the other extreme, for the remaining 10 coins, there are 9 possibilities to select 2 cosecutive ones to be tails).

This gives us a total of 18+22 = 40 possibilities.

5 0
3 years ago
Divide. use patterns and place value. 440 ÷4=
Y_Kistochka [10]
Do 110 times 40 to get 440 you are welcome hope u are good
4 0
3 years ago
Read 2 more answers
Which of the following represents an arithmetic sequence? Group of answer choices -3, -7, -11, -15, -19, -23, ... 7, 11, 15, 19,
Dima020 [189]

Answer:— 3 -7. 4 -13. 5 -19.

Step-by-step explanation:

The solution is table B. In this table ... 7) Which recursive definition represents the sequence {4,6,8,10.

8 0
2 years ago
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