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IgorLugansk [536]
3 years ago
14

If the velocity of a seagull is 0 m/s for a given time period, what can you say about the position of the seagull at the end of

the time period?
Mathematics
1 answer:
lisov135 [29]3 years ago
3 0

Answer:

that the seagull hasn't moved

Step-by-step explanation:

probably dead

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140 fluid ounces increased by 45%
Radda [10]
100\%\ increased\ by\ 45\%=100\%+45\%=145\%\\\\method\ \#1\\\\p\%=\frac{p}{100}\to145\%=\frac{145}{100}=\frac{145:5}{100:5}=\frac{29}{20}\\\\145\%\ of\ 140=\frac{29}{20}\cdot140=29\cdot7=\boxed{203\ (ounces)}\leftarrow answer


method\ \#2\\\\\begin{array}{ccc}140&-&100\%\\x&-&145\%\end{array}\ \ \ cross\ multiply\\\\\\100\cdot x=140\cdot145\ \ \ \ |divide\ both\ sides\ by\ 100\\\\x=\frac{140\cdot145}{100}\\\\\boxed{x=203\ (ounces)}
4 0
3 years ago
Consider the probability that greater than 94 out of 153 people will not get the flu this winter. Assume the probability that a
Hatshy [7]

Answer:

0.8212 = 82.12% probability that greater than 94 out of 153 people will not get the flu this winter.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

p = 0.65, n = 153. So

\mu = E(X) = 153*0.65 = 99.45

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{153*0.65*0.35} = 5.9

Consider the probability that greater than 94 out of 153 people will not get the flu this winter

This probability is 1 subtracted by the pvalue of Z when X = 94. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{94 - 99.45}{5.9}

Z = -0.92

Z = -0.92 has a pvalue of 0.1788

1 - 0.1788 = 0.8212

0.8212 = 82.12% probability that greater than 94 out of 153 people will not get the flu this winter.

7 0
3 years ago
What is the mean of 8,7,6,9,8.5,7.5,10,5.5,7,9,8.5,7,9.5,8,8.5
jek_recluse [69]

Answer:

the mean is 7.93

Step-by-step explanation:

min5.5

median8

max10

7 0
3 years ago
I NEED HELP!!!
andrey2020 [161]

Answer:

<h2>B. The amount of fuel used was lowest at speeds around 60km/h.</h2>

Step-by-step explanation:

The decreasing part is from (20,13) to (60,6), which gives an average rate of

r=\frac{6-13}{60-20}=-\frac{7}{40}=-0.175

Then, we have an increasing part from (60,6) to (120,10), which gives an average rate of

r=\frac{10-6}{120-60}=\frac{4}{60}=0.067

Basically, at 60 km/h the fuel used was 6 liters per 100 kilometers. Notice that the other velocities make the car to use more liters per kilometers.

Therefore, the amount of fuel used was lowest at speeds around 60 km/h.

6 0
3 years ago
9) Find the average rate of change for the function modeled by the graph 5 points
ale4655 [162]

Answer:

4

Step-by-step explanation:

6 0
3 years ago
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