Answer
given,
k = 250 N/m
q = 900 N/m³
(FSp)s=−kΔs−q(Δs)^3
work done = Force x displacement

limits are x = 0 to x = 0.15 m
work done

![W = [\dfrac{kx^2}{2}+\dfrac{qx^4}{4}+ C]_0^0.15](https://tex.z-dn.net/?f=W%20%3D%20%5B%5Cdfrac%7Bkx%5E2%7D%7B2%7D%2B%5Cdfrac%7Bqx%5E4%7D%7B4%7D%2B%20C%5D_0%5E0.15)

W = 3.375 + 0.1139
W = 3.3488 J
b) % cubic term =
% cubic term =
Answer:

Explanation:
Let's start by writing the equations of the forces along the two directions:
- Vertical:

where
N is the normal reaction
is the angle between the road and the horizontal
(mg) is the weight of the car, with m being its mass and g the acceleration of gravity
- Horizontal:

where
v is the speed of the car
r is the radius of the turn
Dividing the 2nd equation by the 1st one, we get:

In this problem:
(radius of the turn)
is the speed

Substituting, we find:

The airplane is tracked for another 123° in the vertical eastwest plane
I): Speed=Distance/Time
=65-30 km/12:30-12:00 hrs
=35 km/00:30hrs
=3500 m/1800 s
=1.94m/s
ii): Average Speed=Total Distance/Total Time
=100000 m/7200 s
=13.88 m/s
iii):No because it has different speeds at
different time intervals
Explanation:
the only difference between the two is one group is powered by battery and the other group is plugged into the wall.