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Reil [10]
3 years ago
6

Which contributions did Galileo make to the model of the solar system? Select two options.a mathematical model for the orbits of

the planetsscientifically accurate data on planetary orbitsdata that showed that planets reflected sunlight similar to Earth’s moonthe idea that stars are other suns that do not moveobservations of the moons of Jupiter rotating around the gas giant
Physics
1 answer:
Gemiola [76]3 years ago
7 0

Answer:

Data that showed that planets reflected sunlight similar to Earth's moon

Observations of the moons of Jupiter rotating around the gas giant

Explanation:

Two of Galileo's contributions to the model of the solar system which he was able to observe with the aid of a early version of the modern telescope which he built himself, following the invention of the 'spyglass' are;

1) The phases of Venus motion round the Sun which is similar to the motion of the moon round the Earth that showed that planets in orbit of the Sun reflected sunlight like the Moon

2) The four moons that rotate around Jupiter.

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How fast much an 816kg Volkswagen travel to have the same momentum as (a) a 2650kg Cadillac going 16.0 km/h? (b) a 9080-kg truck
Katyanochek1 [597]

Answer:

Explanation:

From the given information:

the car's momentum = momentum of the truck

∴

(a) 816 kg × v = 2650 kg × 16.0 km/h

v = (2650 kg × 16.0 km/h) /  816 kg

v = 51.96 km/hr

(b) 816 kg × v = 9080 kg × 16.0 km/h

v = (9080 kg × 16.0 km/h) /  816 kg

v = 178.04 km/hr

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3 years ago
The ________________ is the measure of how far the pendulum is offset (or pulled back) from a vertical position when it is relea
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B. Amplitude

It is the maximum distance from the equilibrium point of the pendulum.
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3 years ago
An object moves 2.5 m. This is an example of a _______. Question 3 options: direction distance velocity speed
Hitman42 [59]
Distance, since distance represents how far something has travelled, which would be in our case 2.5m.
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3 years ago
Read 2 more answers
An object is dropped from a height of 75.0 m above ground level. (a) Determine the distance traveled during the first second. (b
lys-0071 [83]

Answer:

a)Distance traveled during the first second = 4.905 m.

b)Final velocity at which the object hits the ground = 38.36 m/s

c)Distance traveled during the last second of motion before hitting the ground = 33.45 m

Explanation:

a) We have equation of motion

             S = ut + 0.5at²

     Here u = 0, and a = g

              S = 0.5gt²

    Distance traveled during the first second ( t =1 )

              S = 0.5 x 9.81 x 1² = 4.905 m

   Distance traveled during the first second = 4.905 m.

b)  We have equation of motion

            v² = u² + 2as

      Here u = 0, s= 75 m and a = g

           v² = 0² + 2 x g x 75 = 150 x 9.81

           v = 38.36 m/s

      Final velocity at which the object hits the ground = 38.36 m/s

c) We have S = 0.5gt²

                   75 = 0.5 x 9.81 x t²

                    t = 3.91 s

   We need to find distance traveled last second

   That is

          S = 0.5 x 9.81 x 3.91² - 0.5 x 9.81 x 2.91² = 33.45 m

   Distance traveled during the last second of motion before hitting the ground = 33.45 m

       

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