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3 years ago

What mistake did Carl make?

Physics

2 answers:

True [87]3 years ago

8 0

Answer:

He did not multiply the chlorine and oxygen atoms by the coefficient 4

Explanation:

otez555 [7]3 years ago

6 0

Answer:

The correct answer is:

'He did not multiply the chlorine and oxygen atoms by the coefficient 4'.

Explanation:

Number of atoms in $4 Ca(ClO_3)_2$

The 4 in front of molecular formula of calcium chlorate is its coefficient . it tells us about the molecules or moles of compound.

Number of calcium in 1 molecule of calcium chlorate = 1

Calcium atoms in 4 molecule of calcium chlorate = 1 × 4 = 4

Number of calcium in 1 molecule of calcium chlorate = 2

Chlorine atoms in 4 molecule of calcium chlorate = 2 × 4 = 8

Number of oxygen in 1 molecule of calcium chlorate = 3 × 2 = 6

Oxygen atoms in 4 molecule of calcium chlorate = 6 × 4 = 24

So, number of atoms of different elements calculated by Carl was wrong as he didn't multiplied the coefficient 4 with chlorine and oxygen atoms.

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true of false: tires should always be filled to the maximum pressure indicated on the side of the tire

fenix001 [56]

Given what we know about driver and road safety precautions, we can confirm that the statement " tires should always be filled to the maximum pressure indicated on the side of the tire" is false.

<h3>Why should tires not be filled to the maximum air pressure?</h3>

Tires should never be filled to the maximum air pressure.
This would cause the tire to have no room for shifts.
Under normal conditions in the case of a popped tire, the tire will gradually lose air, needing to be inflated.
<u>This presents no danger to the driver if identified on time.</u>
Under conditions of increased pressure, the tire can explode instead of losing air gradually.
This causes the loss of control of the vehicle and danger to the driver and others.

Therefore, we can confirm that the statement " tires should always be filled to the maximum pressure indicated on the side of the tire" is false given that filling the tires to the max allowed pressure greatly increases the odds of the tire exploding and causing the driver to lose control of the car.

To learn more about road safety visit:

brainly.com/question/1260121?referrer=searchResults

4 0

2 years ago

Read 2 more answers

What is the resistance of a 3.5m copper wire that has a cross-sectional area of 5.26 x 10-6 m2?

mestny [16]

R=ρ $\frac{L}{A}$

Where, R is resistance

ρ is resistivity,

L is length and

A is cross sectional area

Given, L= 3.5m

A=5.26 x 10⁻⁶ m²

ρ=1.68×10⁻⁸ ohms m

∴ R= $\frac{(1.68)(3.5)}{5.26*100}$

⇒ R=1.11×10⁻² ohms

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3 years ago

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An object of mass(0.8kg) is attached to massless string of length (2.0),and swung with a tangential velocity of (3.0m/s) what is

Novay_Z [31]

Answer:

3.6 N

Explanation:

The magnitude of centripetal force in this case is equal to the magnitude of tension in the spring.

The formula is :

T= mv²/r ------where T is tension

m= mass of object =0.8 kg

v= velocity of object {tangential velocity} = 3.0 m/s

r= length of string = 2m

Applying the formula with real values;

T= mv²/r

T= {0.8 * 3²} / 2

T= { 7.2}/2 = 3.6 N

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3 years ago

A plane is flying horizontally with speed 237 m/s at a height 1620m above the ground when a package is dropped for the plane. Th

Thepotemich [5.8K]

1. 0.5g*t^2 = 2010 m.

4.9t^2 = 2010.

t = 20.3 s. = Fall time.

D = Xo*t. = 193m/s * 20.3s = 3909 m.

2. V=sqrt(Xo^2+Yo^2)=sqrt(193^2+58^2) = 202 m/s.

3. Vo*t + 0.5g*t^2 = 2010 m.

58*t + 4.9*t^2 = 2010.

4.9t^2 + 58t - 2010 = 0.

Use Quadratic Formula.

t = 15.2 s. = Fall time.

D = 193m/s * 15.2s = 2934 m.

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IgorLugansk [536]

D) There will be less available for other living things.

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