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jeyben [28]
2 years ago
13

Why is it so difficult for astronomers to see new stars in the process of birth?

Physics
1 answer:
vekshin12 years ago
4 0
Birth happens very quickly, so it is hard to "catch" stars in the act. - most stars are born inside dusty clouds, which block any light that may be coming from the stars.
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Why are objects that fall near earths surface rarely in free fall?
marissa [1.9K]

"Free fall" means that gravity is the ONLY force acting on the object.  If there's air resistance, then it isn't free-fall.  

Objects that fall near earths surface are ALWAYS falling through air, unless they're inside some kind of a vacuum chamber with all the air removed from it.

8 0
3 years ago
true or false Newtons's First Law states "Acceleration depends on the mass of the object and the unbalanced force applied"
babunello [35]
False, his first law states: An object that's in motion will remain in motion at a constant velocity unless it's acted on by an unbalanced force.

8 0
3 years ago
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The speed limmit on an interstate highway is posted at 75mi/h. What is the speed in kilometers per hour? In feet per second?
jok3333 [9.3K]

I uploaded the answer to a file hosting. Here's link:

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3 years ago
Two students are running down the hallway towards each other. Student 1 has a mass of 107kg and is running to the right at 4.1m/
antiseptic1488 [7]

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3 0
3 years ago
During what time interval was the object traveling most quickly?
anygoal [31]

ANSWER

0s to 3s

EXPLANATION

To find the time interval where the object was traveling more quickly, we have to find the velocity of the object during each interval.

From a position-time graph, we can obtain the velocity of the object from the slope of the graph in each interval. To find those slopes, we just have to divide the vertical difference by the time interval.

The interval from 0s to 3s:

v=\frac{7-3}{0-3}=-\frac{4}{3}m/s

The interval from 3s to 5s and the interval from 7s to 8s have a horizontal line, so the slope is zero and therefore the velocity is zero - meaning that the object was not moving during these periods.

The interval from 5s to 7s,

v=\frac{5-3}{7-5}=\frac{2}{2}=1m/s

And the interval from 8s to 12s,

v=\frac{0-5}{12-8}=-\frac{5}{4}m/s

Two of these three velocities are negative. Negative velocity indicates that the object is moving backward.

From these velocities, the greatest one, in absolute value, is the one between 0s to 3s. During this interval, the object is moving backward but at the greatest velocity.

3 0
1 year ago
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