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3 years ago

Explain what distinguishes acute and chronic sports injuries.

Physics

2 answers:

notsponge [240]3 years ago

6 0

Answer:

an acute injury can be severe and be like shin splint to where it hurt super bad to roll them out.

Explanation:

vfiekz [6]3 years ago

3 0

Answer:

An acute injury is sudden and severe such as a broken bone. A chronic injury develops and worsens over an extended period of time like shin splints

Explanation:

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Which statement about subatomic particles is not true?

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Answer:

B. is the right answer

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A certain frictionless simple pendulum having a length L and mass M swings with period T. If both L and M are doubled, what is t

vampirchik [111]

The new period is D) √2 T

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<h3>Further explanation</h3>

Let's recall Elastic Potential Energy and Period of Simple Pendulum formula as follows:

$\boxed{E_p = \frac{1}{2}k x^2}$

where:

<em>Ep = elastic potential energy ( J )</em>

<em>k = spring constant ( N/m )</em>

<em>x = spring extension ( compression ) ( m )</em>

$\texttt{ }$

$\boxed{T = 2\pi \sqrt{ \frac{L}{g} }}$

where:

<em>T = period of simple pendulum ( s )</em>

<em>L = length of pendulum ( m )</em>

<em>g = gravitational acceleration ( m/s² )</em>

Let us now tackle the problem!

$\texttt{ }$

<u>Given:</u>

initial length of pendulum = L₁ = L

initial mass = M₁ = M

final length of pendulum = L₂ = 2L

final mass = M₂ = 2M

initial period = T₁ = T

<u>Asked:</u>

final period = T₂ = ?

<u>Solution:</u>

$T_1 : T_2 = 2\pi \sqrt{ \frac{L_1}{g} }} : 2\pi \sqrt{ \frac{L_2}{g} }}$

$T_1 : T_2 = \sqrt{L_1} : \sqrt{L_2}$

$T : T_2 = \sqrt{L} : \sqrt{2L}$

$T : T_2 = 1 : \sqrt{2}$

$\boxed {T_2 = \sqrt{2}\ T}$

$\texttt{ }$

<h3>Learn more</h3>

Kinetic Energy : brainly.com/question/692781

Acceleration : brainly.com/question/2283922

The Speed of Car : brainly.com/question/568302
Young Modulus : brainly.com/question/9202964
Simple Harmonic Motion : brainly.com/question/12069840

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<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Elasticity

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Answer:

4km/hr

Explanation:

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2 years ago

A truck and a car hitting a wall

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Answer:

Explanation:

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2 years ago

It took 150 joules to lift a rock 1.5 meters into the air. How much force did it take to left the rock?

Semmy [17]

Hi there!

We can use the equation:

$\large\boxed{{W = F \cdot d}}$

W = Work (J)

F = Force (N)

d = displacement (m)

We can rearrange to solve for force:

$\large\boxed{F = \frac{W}{d}}$

Plug in the givens:

$F = \frac{150}{1.5} = \boxed{100N}$

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1 year ago