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DerKrebs [107]
3 years ago
14

The tape in a videotape cassette has a total

Physics
1 answer:
Softa [21]3 years ago
5 0

Answer:

1.37 rad/s

Explanation:

Given:

Total length of the tape is, d= 297 m

Total time of run is, t = 2.1 hours

We know, 1 hour = 3600 s

So, 2.1 hours = 2.1 × 3600 = 7560 s

So, total time of run is, t= 7560 s

Inner radius is, r = 10\ mm = 0.01\ m


Outer radius is, R = 47\ mm = 0.047\ m


Now, linear speed of the tape is, v =\frac{d}{t}=\frac{297}{7560}=0.039\ m/s


Let the same angular speed be \omega.

Now, average radius of the reel is given as the sum of the two radii divided by 2.

So, average radius is, R_{avg}=\frac{R+r}{2}=\frac{0.047+0.01}{2}=\frac{0.057}{2}=0.0285\ m


Now, common angular speed is given as the ratio of linear speed and average radius of the tape. So,

\omega=\dfrac{v}{R_{avg}}\\\\\\\omega=\dfrac{0.039}{0.0285}\\\\\\\omega=1.37\ rad/s


Therefore, the common angular speed of the reels is 1.37 rad/s.

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The maximum dimension = √ (2.44 × 10^-6) cm^2.

The maximum dimension= 1.56 × 10^-3 cm.

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