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marshall27 [118]
3 years ago
13

Do you know the answer? Help me!

Mathematics
2 answers:
elena55 [62]3 years ago
7 0
It shows 8 triangles
nataly862011 [7]3 years ago
3 0
A. 8


QRP
QPT
TPS
TRS
SPR
STP
QTS
QRS

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2x + 15<br> 4x - 1<br> SOLVE FOR X<br> WILL GIVE BRAINLEST
musickatia [10]
2x+15=4x-1
16=2x
8=x

hope this helps!
4 0
3 years ago
Jack is 4 times as old as lacey. 7 years ago the sum of their age was 61. how old are they now?
BaLLatris [955]
I am guessing Jack is 51 and Lacey is 17.

7 0
3 years ago
Which of the following would be equivalent to 11 to the 8th power over 11 to the 3rd power
maw [93]
11 x 11 to the 4th power
3 0
4 years ago
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please help me, I'm stuck on the second one. ​Also for i) i got angle ABD because angles in a semicircle measures 90 degree and
True [87]

Answer:

i)

  • <em>DA is diameter and AX is tangent to circle</em>

<u>Your answer is correct</u>

  • m∠ABD = 90°, m∠DAX = 90°

ii)

<u>Given m∠BAX = 42° and ∠DAB is complementary with BAX ⇒ </u>

  • m∠DAB = 90° - 42° = 48°

<u>DC = BC ⇒ intercepted arcs are same ⇒ </u>

  • ∠CDB = ∠BDC

<u>mDC = mCB ⇒ mDCB = ∠DAB = 48° ⇒ </u>

  • m∠CDB = m∠BDC = 1/2*48 = 24°

iii)

∠CBA

<u>∠CBA is supplementary with ∠ADC as opposite angles of cyclic quadrilateral (∠ADB = ∠BAX = 42°)</u>

  • m∠ADC = m∠ADB  + m∠CDB = 42° + 24° = 68°
  • m∠CBA = 180° - m∠ADC = 180° - 68° = 112°

∠BAE

EA║CB and AB is transversal ⇒ CBA and BAE are supplementary angles:

  • m∠BAE = 180° - 112° = 68°

∠DCE

  • ∠DCE = ∠DCB - ∠BCE
  • m∠DCB = 180° - m∠DAB = 180° - 48° = 132°
  • m∠BCE = 180° - m∠BAE = 180° - 68° = 112°
  • ∠DCE = 132° - 112° = 20°
5 0
3 years ago
Which of the following is a composite number between 20 and 40
aniked [119]
20, 21, 22, 24, 25, 26, 27, 28, 30, 32, 33, 34, 35, 36, 38, 39, 40


7 0
3 years ago
Read 2 more answers
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