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marshall27 [118]
3 years ago
13

Do you know the answer? Help me!

Mathematics
2 answers:
elena55 [62]3 years ago
7 0
It shows 8 triangles
nataly862011 [7]3 years ago
3 0
A. 8


QRP
QPT
TPS
TRS
SPR
STP
QTS
QRS

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Is there a triangle that has a greater area than its perimeter?
zzz [600]

Answer:

no

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shajajs

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3 years ago
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Modulation is the process of a)Spinning a wheel to generate a sine wave b)Increasing the amplitude of a sine wave c)Changing one
hram777 [196]

Answer: C) Changing one or more properties of a sine wave in response to data.

Step-by-step explanation:

Modulation is primarily used in telecommunications sector. It the process by which data is transmitted via electrical signals. It is the process of imposing an input signal on to a wave carrier. It is the pillar of data communication that enables the use information carriers of signals that are electrical and optical. Altering the carrier/ periodic waveform results in Modulation. The amplitude frequency and phase are conveyed. There are different types of Modulation which includes: amplitude Modulation, frequency Modulation, and phase Modulation.

5 0
3 years ago
The variable in a relation who’s value depends on the value of the independent variable is called what?
Viefleur [7K]
That is called the dependent variable. It depends upon the value of the independent variable.

f(x)=y

So we can see by inspection that the dependent variable y value depends upon the input value of the independent variable x

Any questions please feel free to ask. Thanks
3 0
3 years ago
Help me please ASAP please help
Mekhanik [1.2K]

Answer:

the volume is 15.7 in. 3............

4 0
3 years ago
Given that the expression x³_ ax² + bx+c leaves the same remainder when divided by x + 1 or x-2, find 'a' in terms of 'b'.​
goblinko [34]

Answer:

Hi,

a=b+3

Step-by-step explanation:

\begin{array}{c||c|c|c|c}&x^3&x^2&x&1\\---&---&---&---&---\\&1&-a&b&c\\x=-1&&-1&a+1&-a-b-1\\---&---&---&---&---\\&1&-a-1&a+b+1&c-a-b-1\\\end{array}

\begin{array}{c||c|c|c|c}&x^3&x^2&x&1\\---&---&---&---&---\\&1&-a&b&c\\x=2&&2&4-2a&2b+8-4a\\---&---&---&---&---\\&1&2-a&b+4-2a&c+2b+8-4a\\\end{array}

Thus:

c+2b+8-4a=c-a-b-1

3b-3a=-9

<u>a=b+3</u>

5 0
2 years ago
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