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GenaCL600 [577]
3 years ago
12

Can someone please answer. There is one problem. There's a picture. Thank you!!!

Mathematics
1 answer:
djverab [1.8K]3 years ago
3 0
The answer for your question is C. The reason is I multipled 15 and 6 which gave me 90 and that is closest to the answer C which is 72.73. Hope this helps:)
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2 years ago
Which equations could be used to solve for the unknown lengths of △ABC? Check all that apply.
GuDViN [60]

Applying the trigonometric ratios, the equations that can be used are:

sin 45 = BC/9

cos 45 = BC/9

<h3>How to Apply the Trigonometric Ratio?</h3>

In the given image below, to find the unknown lengths of the triangle, we would apply the following trigonometric ratios:

To find AC, use the cosine ratio, CAH.

To find BC, use the sine ratio, SOH.

sin 45 = opp/hyp = BC/9

sin 45 = BC/9

cos 45 = adj/hyp = BC/9

cos 45 = BC/9

Learn more about the trigonometric ratios on:

brainly.com/question/10417664

#SPJ1

6 0
2 years ago
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