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Law Incorporation [45]
3 years ago
11

A space station moves in a circular orbit around Earth. Which of the following statements describes the centripetal force acting

on the space station?
A. The force is acting in the direction of motion.
B. The force is directed toward the space station.
C. The force is directed toward the center of Earth.
D. The force is acting opposite the direction of motion.
Physics
1 answer:
drek231 [11]3 years ago
8 0
C.
because centripetal means that force only acts in the center of body in motion
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Suppose the acceleration of an elevator is 1/2 g upward, then what is the reading on the scale in the elevator.
Irina-Kira [14]

Answer:

c. 3/2 mg

Explanation:

Given that the acceleration of an elevator is 1/2 g upward.

The reading on the scale of the elevator is the net external force acting on the elevator.

Let the force F acting on the elevator as shown,

By using Newton's 2nd law, F_{net}=ma

where, F_{net} is the net force acting on the elevator.

m is the mass of the elevator,

a is the acceleration of the elevator, as given a=1/2 g upward.

So, F_{net}=m\times \frac 1 2 g

F-mg=m\times \frac 1 2 g \\\\F=mg+ \frac 1 2 mg \\\\F= \frac 3 2 mg.

So, the reading on the scale in the elevator is \frac 3 2 mg.

Hence, option (c) is correct.

4 0
3 years ago
A comet is in an elliptical orbit around the Sun. Its closest approach to the Sun is a distance of 4.7 1010 m (inside the orbit
Lubov Fominskaja [6]

Answer:

58515.9 m/s

Explanation:

We are given that

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We have to find the speed (vf).

Work done by surrounding particles=W=0 Therefore, initial energy is equal to final energy.

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\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2}=\frac{1}{2}v^2_f

v^2_f=2(\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2})

v_f=\sqrt{2(\frac{1}{2}v^2_i-\frac{GM}{d_1}+\frac{GM}{d_2})}

Using the formula

v_f=\sqrt{v^2_i+2GM(\frac{1}{d_2}-\frac{1}{d_1})}

v_f=\sqrt{(9.5\times 10^4)^2+2\times 6.7\times 10^{-11}\times 1.98\times 10^{30}(\frac{1}{6\times 10^{12}}-\frac{1}{4.7\times 10^{10})}

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G=6.7\times 10^{-11}

v_f=58515.9 m/s

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