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DaniilM [7]
3 years ago
6

When the electron is moving in the plane of the page in the direction indicated by the arrow, the force on the electron is direc

ted:_____
a. into the page.
b. toward the left
c. toward the right
d. toward the bottom of the page.
e. toward the top of the page.
f. out of the page.
Physics
1 answer:
Serga [27]3 years ago
8 0

Answer: F

Out of the page.

Explanation:

For an electron with a charge of -e, the magnitude of the force on it is F = BeV

Where

F = force on the electron

e = charge ( electrons )

V = velocity

B = magnetic field

F is the force acting on all the electrons in a wire which gives rise to the F = BIL

Where

I = current

L = length of the wire

The force F is always at the right angle to the particle's velocity and its direction can be found using the left hand rule.

When the electron is moving in the plane of the page in the direction indicated by the arrow, the force on the electron is directed out of the page.

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Calculate the initial (from rest) acceleration of a proton in a 5.00 x 10^6 N/C electric field (such as created by a research Va
julsineya [31]

Answer:

Acceleration of the proton will be equal to 4.79\times 10^{14}m/sec^2

Explanation:

We have given electric field E=5\times 10^6N/C

Mass of proton is equal to m=1.67\times 10^{-27}kg

And charge on proton is equal to e=1.6\times 10^{-19}C

Electrostatic force will be responsible for the motion of proton

Electrostatic force will be equal to F=qE=1.6\times 10^{-19}\times 5\times 10^6=8\times 10^{-13}N

According to newton law force on the proton will be equal to F = ma, here m is mass of proton and a is acceleration

This newton force will be equal to electrostatic force

So 1.67\times 10^{-27}\times a=8\times 10^{-13}

a=4.79\times 10^{14}m/sec^2

So acceleration of the proton will be equal to 4.79\times 10^{14}m/sec^2

5 0
3 years ago
11. A bowling ball has a mass of 7 kg and a velocity of 3 m/s.<br> (A) What is the ball's momentum?
DaniilM [7]

Answer: 21 kg x m/s

Momentum can be found using the equation p = mv, or momentum = mass times velocity.

Therefore, to find the momentum of the bowling bowl, you can plug the mass and velocity values into the equation to get p = (7kg)(3m/s)

Solve the equation to get a momentum of 21kg x m/s

I hope I could help :)

7 0
3 years ago
What is<br><img src="https://tex.z-dn.net/?f=3%20%5Csqrt%7B125x12%7D%20" id="TexFormula1" title="3 \sqrt{125x12} " alt="3 \sqrt{
Whitepunk [10]

Answer:

What are you asking me? Tex{t} x1|2?3 squ{R] oo|t?

Explanation:

5 0
4 years ago
5. A hollow cylinder of mass m, radius Rc, and moment of inertia I = mRc2 is pushed against a spring (with spring constant k) co
Makovka662 [10]

Explanation:

(a) Draw a free body diagram of the cylinder at the top of the loop.  At the minimum speed, the normal force is 0, so the only force is weight pulling down.

Sum of forces in the centripetal direction:

∑F = ma

mg = mv²/RL

v = √(g RL)

(b) Energy is conserved.

EE = KE + RE + PE

½ kd² = ½ mv² + ½ Iω² + mgh

kd² = mv² + Iω² + 2mgh

kd² = mv² + (m RC²) ω² + 2mg (2 RL)

kd² = mv² + m RC²ω² + 4mg RL

kd² = mv² + mv² + 4mg RL

kd² = 2mv² + 4mg RL

kd² = 2m (v² + 2g RL)

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8 0
3 years ago
What is the approximate feed point impedance at the center of a two-wire folded dipole antenna?
Shalnov [3]

The approximate feed point impedance at the center of a two-wire folded dipole antenna will be 300 ohms.

<h3>What is impedance?</h3>

The combined effect of resistance and reactance in a circuit creates impedance, which opposes alternating current.

Consider the flat twin ribbon TV antenna wire with a 300 ohm impedance. A folded dipole's impedance is 4 times that of a half-wave dipole,

A folded dipole's impedance is found as;

Folded dipole's impedance = 4 × half-wave dipole

Half-wave dipole = 73 ohms

Folded dipole's impedance = 73 × 4

Folded dipole's impedance =292 ohms

Folded dipole's impedance ≈ 300 ohms.

To learn more about the impedance, refer to the link;

https://brainly.in/question/12433840

#SPJ1

7 0
2 years ago
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