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victus00 [196]
3 years ago
14

Suppose the acceleration of an elevator is 1/2 g upward, then what is the reading on the scale in the elevator.

Physics
1 answer:
Irina-Kira [14]3 years ago
4 0

Answer:

c. 3/2 mg

Explanation:

Given that the acceleration of an elevator is 1/2 g upward.

The reading on the scale of the elevator is the net external force acting on the elevator.

Let the force F acting on the elevator as shown,

By using Newton's 2nd law, F_{net}=ma

where, F_{net} is the net force acting on the elevator.

m is the mass of the elevator,

a is the acceleration of the elevator, as given a=1/2 g upward.

So, F_{net}=m\times \frac 1 2 g

F-mg=m\times \frac 1 2 g \\\\F=mg+ \frac 1 2 mg \\\\F= \frac 3 2 mg.

So, the reading on the scale in the elevator is \frac 3 2 mg.

Hence, option (c) is correct.

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