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Liula [17]
3 years ago
13

All of the waves in the electromagnetic spectrum are _______ waves.

Physics
2 answers:
Natalija [7]3 years ago
7 0

Answer: All of the waves in the electromagnetic spectrum are transverse waves.

Explanation:

Electromagnetic spectrum is a continuum of electromagnetic waves. These waves are arranged according to wavelength and frequency.

Electromagnetic waves are transverse in nature. In the transverse wave, the particles of vibrations in the medium travels perpendicular to the direction of propagation of the wave.

They travel with the speed of the light in the form of sinusoidal wave.

Therefore, all of the waves in the electromagnetic spectrum are transverse waves

crimeas [40]3 years ago
5 0
<span>All of the waves in the electromagnetic spectrum are transverse waves.</span>
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How long will it take a car to accelerate from 15.2 to 23.5 m/s if the car has an average acceleration of 3.2 m/s?
Nuetrik [128]
 a =  ( V2 - V1)/( t2 - t1)
 3.2 =  ( 23.5m/s - 15.2m/s)/(t - 0)
3.2m/s = 8.3/t
t(3.2) = 8.3
t = 8.3/3.2
t = 2.59 seconds
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How does the law of conservation apply to Earth's Energy Budget?
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Answer:

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2 years ago
When aluminum foil is formed into a loose ball, it can float on water. But when the ball of foil is pounded flat with a hammer,
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Air caught in the ball of foil makes the ball less dense than water
8 0
3 years ago
a mass on a spring vibrates in simple harmonic motion at an amplitude of 8.0 cm. if the mass of the object is 0.20kg and the spr
Reil [10]

Answer:

4.06 Hz

Explanation:

For simple harmonic motion, frequency is given by

f=\frac {1}{2\pi}\times \sqrt{\frac {k}{m}} where k is spring constant and m is the mass of the object.

Substituting 0.2 Kg for mass and 130 N/m for k then

f=\frac {1}{2\pi}\times \sqrt{\frac {130}{0.2}}=4.057670803\\f\approx 4.06 Hz

5 0
3 years ago
In the final situation below, the 8.0 kg box has been launched with a speed of 10.0 m/s across a frictionless surface. Find the
Murljashka [212]

Answer:

the energy of the spring at the start is 400 J.

Explanation:

Given;

mass of the box, m = 8.0 kg

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Apply the principle of conservation of energy to determine the energy of the spring at the start;

Final Kinetic energy of the box = initial elastic potential energy of the spring

K.E = Ux

¹/₂mv² = Ux

¹/₂ x 8 x 10² = Ux

400 J = Ux

Therefore, the energy of the spring at the start is 400 J.

8 0
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