Answer:
2 g/mL
Explanation:
Density can be calculated using the ratio:
Density = mass (g) / volume (mL)
Since you have been given both the mass and volume of the liquid, you can calculate the density.
Mass = 6 grams (g)
Volume = 3 milliliters (mL)
Density = mass / volume
Density = 6 g / 3 mL
Density = 2 g/mL
Answer:
The additional electron does not affect the atomic number nor the mass number. The atomic mass is the sum of neutrons and protons. Electrons are not accounted in atomic mass as their mass is so small, approximately 1/1,836 of a protons mass. Atomic number is the total number of protons of an atom. Chlorine taking in another electron will not change its atomic number. In an ion, the atomic number and atomic mass do not change from the original.
A scientific theory is a well tested explanation of a natural phenomenon.
Answer:
-248.425 kJ/mol
Explanation:
This question can be done by simply taking the ratios:
Since the given the heat change for 1.00 mol of
is -373.7 KJ/mol. Let us consider the required Heat Exchange at 0.631 mol of
We can write:


KJ/mol
Answer:
Volume of chlorine = 61.943 mL
Explanation:
Given:
Volume of the water in the Pool = 18,000 gal
also,
1 gal = 3785.412 mL
thus,
Volume of water in pool = 18,000 × 3785.412 = 68,137,470 mL
Density of water = 1.00 g/mL
Therefore,
The mass of water in the pool = Volume × Density
or
The mass of water in the pool = 68,137,470 mL × 1.00 g/mL = 68,137,470 g
in terms of million =
or
= 68.13747 g
also,
1 g of chlorine is present per million grams of water
thus,
chlorine present is 68.13747 g
Now,
volume =
or
Volume of chlorine =
or
Volume of chlorine = 61.943 mL