Nitrogen in this compound has 2 atoms. 2 multiplied by its mass, 14.007, equals 28.014. Divide 28.014 by the molar mass of calcium nitrate: 28.014/164 = 0.17081. Multiply this by 100 to achieve its percentage: 0.17081 x 100 = 17.08%
The cornea is the outer clear, round structure that covers the Iris and the pupil. The Iris is the colored part of the eye.
Answer:
0.24M
Explanation:
The equation for the reaction is given below:
H2SO4 + 2KOH → K2SO4 + 2H2O
From the equation above, we obtained the following information:
nA (mole of acid) = 1
nB (mole of base) = 2
Data obtained from the question include:
Va (volume of the acid) = 12mL
Ca (concentration of the acid) =?
Vb (volume of the base) = 36mL
Cb (concentration of the base) = 0.16 M
The Ca (concentration of the acid) can be obtained as follow:
CaVa/CbVb = nA/nB
Ca x 12 / 0.16 x 36 = 1 /2
Cross multiply to express in linear form as shown below:
Ca x 12 x 2 = 0.16 x 36
Divide both side by 12 x 2
Ca = 0.16 x 36/ 12 x 2
Ca = 0.24M
Therefore, the concentration of the acid is 0.24M
Answer:
Chlorine is found abundantly in earth crust and ocean.
Explanation:
The elements of group 17 are called halogens. These are six elements Fluorine, Chlorine, Bromine, Iodine, Astatine. Chlorine is one of them.
it is greenish-yellow irritating gas.
its melting point is 172.2 K
its boiling point is 238.6 K
It is present in earth crust and ocean abundantly.
In ocean chlorine is found in the form of salt sodium chloride.
About 1.9% mass of sea water consist of chlorine ions.
In earth crust it is present in minerals such as carnallite and sylvite.
it is disinfectant and can kill the bacteria.
it is also used in manufacturing of paper, paints and textile industries.
It is also reported that chlorine can effect the respiratory system, immune system and heart.
Up to some extent it can also effect the organism living in water.
Answer:
9.8 L
Explanation:
The reaction that takes place is:
- 4H₂(g) + CS₂(g) → CH₄(g)+ 2H₂S(g)
At STP, 1 mol of any gas occupies 22.4 L.
We <u>calculate how many moles are there in 2.5 L of CH₄ at STP</u>:
- 2.5 L ÷ 22.4 L/mol = 0.11 mol CH₄
Then we <u>convert CH₄ moles into H₂ moles</u>, using the<em> stoichiometric coefficients of the reaction</em>:
- 0.11 mol CH₄ *
= 0.44 mol H₂
Finally we <u>calculate the volume that 0.44 moles of H₂ would occupy at STP</u>:
- 0.44 mol * 22.4 L/mol = 9.8 L
