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padilas [110]
3 years ago
12

Correct name for #10 please

Chemistry
1 answer:
ira [324]3 years ago
5 0

Answer:

CH₃CH(CH₃)CH(C₃H₇)CH₂CH(CH₃)₂:

4-isopropyl-2-methylpentane.

Explanation:

Step One: Draw the structure formula of this compound. Parentheses in the formula indicate substitute groups that are connected to the carbon atom to the left.

For example, the first (CH₃) indicates that the second carbon atom from the left is connected to:

  • the CH₃- on the left-hand side,
  • the -CH(C₃H₇)CH₂CH(CH₃)₂ on the right-hand side,
  • a hydrogen atom, and
  • an additional CH₃- group that replaced one hydrogen atom.

Each carbon atom in this compound is connected to four other atoms. All bonds between carbon atoms are single bonds.

The C₃H₇ in the second pair of parentheses is the condensed form of CH₃CH₂CH₂-. See the first sketch attached. Groups in parentheses are highlighted.

Step Two: Find the carbon backbone. The backbone of a hydrocarbon is the longest chain of carbon atoms that runs through the compound. See the second sketch attached. The backbone of this compound consists of seven carbon atoms and is highlighted in green. The name for this backbone shall be heptane.

Step Three: Identify and name the substitute groups.

The two substitute groups are circled in blue in the second sketch.

  • The one on the right -CH₃ is a methyl group.
  • The one on the left is branched. \begin{aligned}\text{CH}_3-&\text{CH}-\text{CH}_3\\[-0.5em]&\;|\end{aligned} This group can be formed by removing one hydrogen from the central carbon atom in propane. The name for this group is isopropyl.

Step Four: Number the atoms.

Isopropyl shall be placed before methyl. Start from the right end to minimize the index number on all substitute groups. The methyl group is on carbon number two and the isopropyl group on carbon number four. Hence the name:

4-isopropyl-2-methylheptane.

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Sergeu [11.5K]

Answer:

See Explanation

Explanation:

Let us consider the first two reactions, the initial concentration of CO was held constant and the concentration of Hbn was doubled.

2.68 * 10^-3/1.34 * 10^-3 = 6.24 * 10^-4/3.12 * 10^-4

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The rate of reaction is first order with respect to Hbn

Let us consider the third and fourth reactions. The concentration of Hbn is held constant and that of CO was tripled.

1.5 * 10^-3/5 * 10^-4 = 1.872 * 10^-3/6.24 * 10^-4

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The reaction is also first order with respect to CO

b) The overall order of reaction is 1 + 1=2

c) The rate equation is;

Rate = k [CO] [Hbn]

d) 3.12 * 10^-4 = k [5 * 10^-4] [1.34 * 10^-3]

k = 3.12 * 10^-4  /[5 * 10^-4] [1.34 * 10^-3]

k = 3.12 * 10^-4/6.7 * 10^-7

k = 4.7 * 10^2 mmol-1 L s-1

e) The reaction occurs in one step because;

1) The rate law agrees with the experimental data.

2) The sum of the order of reaction of each specie in the rate law gives the overall order of reaction.

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Which of these solid compounds are most likely to have its dominant bonding mechanism as covalent? (Select all that are true.)
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The compounds that have covalent bonding as their dominant bonding scheme are diamond and silica.

A covalent bond is formed between two nonmetals. Usually, when two nonmetals combine, electrons are shared between the two atoms involved in the bond.

Now, the solids diamond and silica are predominantly covalent solids. The atoms that combine in diamond are carbon atoms(nonmetals) while the atoms that combine in silica are silicon and oxygen (nonmetals also)

Hence, diamond and silica both have covalent bonding as their dominant bonding scheme.

Learn more: brainly.com/question/11527546

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The answer is A. I think
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3 years ago
Read 2 more answers
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