1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
padilas [110]
4 years ago
12

Correct name for #10 please

Chemistry
1 answer:
ira [324]4 years ago
5 0

Answer:

CH₃CH(CH₃)CH(C₃H₇)CH₂CH(CH₃)₂:

4-isopropyl-2-methylpentane.

Explanation:

Step One: Draw the structure formula of this compound. Parentheses in the formula indicate substitute groups that are connected to the carbon atom to the left.

For example, the first (CH₃) indicates that the second carbon atom from the left is connected to:

  • the CH₃- on the left-hand side,
  • the -CH(C₃H₇)CH₂CH(CH₃)₂ on the right-hand side,
  • a hydrogen atom, and
  • an additional CH₃- group that replaced one hydrogen atom.

Each carbon atom in this compound is connected to four other atoms. All bonds between carbon atoms are single bonds.

The C₃H₇ in the second pair of parentheses is the condensed form of CH₃CH₂CH₂-. See the first sketch attached. Groups in parentheses are highlighted.

Step Two: Find the carbon backbone. The backbone of a hydrocarbon is the longest chain of carbon atoms that runs through the compound. See the second sketch attached. The backbone of this compound consists of seven carbon atoms and is highlighted in green. The name for this backbone shall be heptane.

Step Three: Identify and name the substitute groups.

The two substitute groups are circled in blue in the second sketch.

  • The one on the right -CH₃ is a methyl group.
  • The one on the left is branched. \begin{aligned}\text{CH}_3-&\text{CH}-\text{CH}_3\\[-0.5em]&\;|\end{aligned} This group can be formed by removing one hydrogen from the central carbon atom in propane. The name for this group is isopropyl.

Step Four: Number the atoms.

Isopropyl shall be placed before methyl. Start from the right end to minimize the index number on all substitute groups. The methyl group is on carbon number two and the isopropyl group on carbon number four. Hence the name:

4-isopropyl-2-methylheptane.

You might be interested in
Using the information make a graph.
makkiz [27]
Boosting this for more can see
4 0
3 years ago
If you had a 0.200 L solution containing 0.0140 M of Fe3+(aq), and you wished to add enough 1.27 M NaOH(aq) to precipitate all o
Lelechka [254]

Answer:  6.6 ml

Explanation:

If you had a 0.200 L solution containing 0.0140 M of Fe3+(aq), and you wished to add enough 1.27 M NaOH(aq) to precipitate all of the metal, what is the minimum amount of the NaOH(aq) solution you would need to add? Assume that the NaOH(aq) solution is the only source of OH−(aq) for the precipitation.

You have 0.014X0,2 = 0,0028 moles of Fe ion.

You need 0,0028 X 3 = 00084 moles of OH

The NaOH is 1.27 moles/liter

0.084/1.27 =  6.6 ml

8 0
3 years ago
A boy who weighs 30 kg is skateboarding at a speed of 5 m/s. What is the boys kinetic energy?
zheka24 [161]
I’m pretty sure it’s 150 joules
5 0
3 years ago
Which of the following is a strong reducing agent? Explain how you know.
swat32
The answer is: <span>The principal idea here is how r they obtained: 
for example: sodium  u put equal molar concentrations of sodium (Na) and sodium ion (Na+)  together in a beaker , then dip in this solution a platinium wire (zero potential) which is connected to a normal hydrogen electrode (electrode with zero potential)  then u see the reading of the whole circuit 
if it is negtive, this means negative potential which means that the reducing property predominates where Na(reducing agent) is oxidized and electrons r accumulated on the platinum which gives it negative charge 
This means that (Na) is a reducing agent, its strength depends on the value of the potential obtained, and here the table can help you 
If u want to know if it's strong red. agent, look for it in the table, see if it has higher reduction potentail (or lower oxidation potential, same idea) than most other substances then it is reducing agent 
and vice versa 

So if we look at ur examples, u will find that MnO4- is the very strong oxidizing agent (has highest oxidation potential) (lowest reduction potential) 

H+ and H2 are both with zero potential, no redox properties 

And lastly Na and Na+: 
This u can know from ur knowledge in chemistry, that sodium is very rarely found in elemental form and always in the form of ion so u can deduce that Na is the very strong reducing agent 
or u can see the value of its standard oxi or red potetial and deduce which is the predominating form of them. 

I hope this helps</span>
4 0
4 years ago
Why are elements put in a particular group?
lana [24]

Answer:

The columns of the table represent groups, or families, of elements. The elements in a group often look and behave similarly, because they have the same number of electrons in their outermost shell

3 0
3 years ago
Other questions:
  • How would you know if you were eating something with a high alkaline level?
    15·1 answer
  • Which statement describes a chemical property of iron?(1) Iron can be flattened into sheets.(2) Iron conducts electricity and he
    12·1 answer
  • Why is feo named using a roman numeral, iron (ii) oxide, whereas cao named without a roman numeral, calcium oxide?
    11·1 answer
  • After being ignited in a Bunsen burner flame, a piece of magnesium ribbon burns brightly giving off heat and light in this situa
    9·1 answer
  • Math help will give brainliest
    14·2 answers
  • Please help <br><br>look at the image<br>which one is it
    12·1 answer
  • Which of the following best describes the motion of the particles in a piece of steel?
    5·1 answer
  • Convert -12.00 degrees Celsius to the unit Kelvin. 296.15 K 261.15 K -285.15 K -162.85 K
    12·1 answer
  • What characteristics do atoms of manganese- 55, iron-56, and nickel-58 have in common?​
    8·1 answer
  • Which orbital can be modeled by a "peanut" shape?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!