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3 years ago

2. Which set of symbols represents isotopes of the same element?

Chemistry

1 answer:

MariettaO [177]3 years ago

7 0

Answer:

so you can do the maths your self

Explanation:

isotopes are elements with he same proton number but difference in their neutron number

proton number is also known as the atomic number
mass number is the sum of the proton number and the neutron number
mass number = proton number + neutron number

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My atomic number is 35.453.

ruslelena [56]

CL
Chlorine
You wiil find in periodic table :)

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3 years ago

If n=7 and l=6, What are the values of l?

SpyIntel [72]

Wecfifjfjoeoddkcmfkfofofif

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3 years ago

What volume of carbon dioxide gas can be collected from

alisha [4.7K]

Answer:

1.22 L of carbon dioxide gas

Explanation:

The reaction that takes place is:

CaCO₃ + HCl → CaCl₂ + CO₂ + H₂O

First we determine which reactant is limiting:

Calcium carbonate ⇒ 10.0 g CaCO₃ ÷ 100 g/mol = 0.10 mol CaCO₃

Hydrochloric acid ⇒ 0.100 L * 0.50 M = 0.05 mol HCl

So HCl is the limiting reactant.

Now we calculate the moles of CO₂ produced:

0.05 mol HCl * $\frac{1molCO_{2}}{1molHCl}$ = 0.05 mol CO₂

Finally we use PV=nRT to calculate the volume:

P = 1 atm

n = 0.05 mol

T = 25 °C ⇒ 25 + 273.16 = 298.16 K

1 atm * V = 0.05 mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 298.16 K

V = 1.22 L

7 0

3 years ago

Which of the following units is used to measure force ?

Sati [7]

C.) Newton. & it's S.I. Unit of Force.

Hope this helps!

3 0

3 years ago

Read 2 more answers

Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it

lions [1.4K]

Answer: The equilibrium concentration of $COF_2$ is 0.332 M

Explanation:

We are given:

Initial concentration of $COF_2$ = 2.00 M

The given chemical equation follows:

$2COF_2(g)\rightleftharpoons CO_2(g)+CF_4(g)$

Initial: 2.00

At eqllm: 2.00-2x x x

The expression of $K_c$ for above equation follows:

$K_c=\frac{[CO_2][CF_4]}{[COF_2]^2}$

We are given:

$K_c=6.30$

Putting values in above expression, we get:

$6.30=\frac{x\times x}{(2.00-2x)^2}\\\\x=0.834,1.25$

Neglecting the value of x = 1.25 because equilibrium concentration of the reactant will becomes negative, which is not possible

So, equilibrium concentration of $COF_2=(2.00-2x)=[2.00-(2\times 0.834)]=0.332M$

Hence, the equilibrium concentration of $COF_2$ is 0.332 M

4 0

3 years ago