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IceJOKER [234]
3 years ago
10

One tank of gasoline has an octane rating of 140 and another tank of gasoline has an octane rating of 80. to obtain a mixture of

60 gallons with an octane rating of 120, how many gallons should be used from the tank with the octane rating of 80?
Chemistry
1 answer:
lutik1710 [3]3 years ago
8 0
Call x the volume of gas whose octane rating is 140 and y the volume of gas whose octane rating is 80, then:

(1) x*140 + y*80 = 60*120, and

(2) x + y = 60

from (1) 140x + 80y = 7200 => (3) 7x + 4y = 360

from (2) --->                              (4) 4x + 4y = 240

Subtract (4) from (3)

7x - 4x = 360 - 240

3x = 120

=> x = 120/3 = 40

=> y = 120 - 40 = 80

Answer: should be used 80 gallons from tank with the octane rating of 80


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Remember the formula as per the second Law of Newton: F = m*a

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3 years ago
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The oxidation number of nitrogen in the equation increased from -1 in hydrazine on the lefthand side of the reaction equation to zero in nitrogen on the right hand side of the reaction equation. Two electrons were lost in the process as shown.

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