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3 years ago

Force = 2.32 N Acceleration = 0.19 m/s2 Mass= ?

Chemistry

1 answer:

Mkey [24]3 years ago

3 0

mass = 12.2 kg

Explanation:

To find the mass we use the following formula (Newton's Second Law of Motion):

force = mass × acceleration

mass = force / acceleration

mass = 2.32 N / 0.19 m/s²

mass = 12.2 kg

Learn more about:

Newton's Second Law of Motion

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10. The circulatory system transfers nutrients, gases, liquids, and heat around the body.

11. The circulatory system transports heat, which helps regulate temperature.

13. The place where oxygen enters the blood and carbon dioxide leaves the blood. Lungs.

15. A gas that is transported in arteries from the lungs to the rest of the body via the heart. Oxygen.

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2. The heart, blood, and vessels. Circulatory System.

4. Blood in arteries is bright red because it is rich in oxygen.

6. A waste gas that is transported in veins from the body to the lungs via the heart. Carbon di Oxide.

Explanation:

The circulatory system includes blood vessels, blood, and heart. This system provides the body tissues with oxygen and some nutrients. It also carries hormones and eliminates needless waste products.

This transportation takes place between the cells via blood throughout the body. The channel that blood passes through is a blood vessel that is pumped by an organ called heart. The heart directs the blood passing all over the body.

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An element or compound which occurs naturally in the earth is a alloymineralrock.

elena-s [515]

Minerals naturally occur.

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3 years ago

Write the net ionic equation for KNO2 + HCl -> KCl + HNO2

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3 years ago

Suppose that you have 115 mL of a buffer that is 0.460 M in both benzoic acid ( C 6 H 5 COOH ) and its conjugate base ( C 6 H 5

77julia77 [94]

Answer: The maximum volume of HCl that can be added before its buffering capacity is lost is 111.3 mL

Explanation:

We are given:

Concentration of buffer = 0.460 M

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

$pH=pK_a+\log(\frac{[salt]}{[acid]})$

$pH=pK_a+\log(\frac{[C_6H_5COO^-]}{[C_6H_5COOH]})$ .....(1)

We are given:

$pK_a$ = negative logarithm of acid dissociation constant of benzoic acid = 4.2

$[C_6H_5COOH]=0.460M$

$[C_6H_5COO^-]=0.460M$

pH = ?

Putting values in equation 1, we get:

$pH=4.2+\log(\frac{0.460}{0.460})\\\\pH=4.2$

When the pH of the buffer changes by 1 unit, the buffering capacity is said to be lost.

pH change for loosing buffer capacity = [4.2 - 1] = 3.2

Calculating the ratio of conjugate base and its acid by using equation 1:

$pK_a$ = 4.2

pH = 3.2

Putting values in equation 1, we get:

$3.2=4.2+\log(\frac{[C_6H_5COO^-]}{[C_6H_5COOH]})\\\\\frac{[C_6H_5COO^-]}{[C_6H_5COOH]}=0.1$

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$ ......(2)

For benzoic acid and its conjugate base:

Molarity of benzoic acid and its conjugate base = 0.460 M

Volume of solution = 115 mL

Putting values in equation 2, we get:

$0.460=\frac{\text{Moles of benzoic acid and its conjugate base}\times 1000}{115mL}\\\\\text{Moles of benzoic acid and its conjugate base}=\frac{0.460\times 115}{1000}=0.053mol$