1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
yaroslaw [1]
3 years ago
12

Name the following compounds:

Chemistry
1 answer:
ankoles [38]3 years ago
3 0
A) cesium chloride
B) barium oxide
C) potassium sulfide
D) beryllium chloride
E) hydrogen bromide
F) aluminum fluoride
You might be interested in
Calculate the given mass in 0.5 mol. Of CH4 <br><br>​
xz_007 [3.2K]

Answer:

8 grams

Explanation:

The molar mass of CH4 is about 16 grams per mol.  So you get the answer by mutlitplying 0.5 by 16, (cancel out moles by placing 1 on the bottom of the fraction).

3 0
3 years ago
Read 2 more answers
Sea, sand, sky, palms – made almost all of
andrezito [222]

Answer:

sup

Explanation:

3 0
3 years ago
Name two helper organs in the digestive system that food does not pass through
Gala2k [10]
The pancreas, liver, and gallbladder. Hope that helps!
8 0
3 years ago
Read 2 more answers
Which of the following is false? Charged molecules are insoluble in water. Hydrophobic molecules tend to be nonpolar and hydroph
inysia [295]

Answer:

Number 1 is false

Explanation:

1.- Charged molecules are insoluble in water. The statement is false, charged molecules are soluble in water and this is the main characteristic of charged molecules.

2.- Hydrophobic molecules tend to be nonpolar and hydrophilic molecules tend to be polar. This is true, hydrophobic molecules are non polar and hydrophilic molecules are polar.

3.- Gasoline has partial positive and negative charges which allows it to dissolve in water. This is true, gasoline is soluble in water.

4.- NH3 dissolves in water because its molecules form hydrogen bonds with water. This is true, NH3 interact with water because they can form hydrogen bonds.

5.- Hydrophobic molecules prefer to interact with each other in an aqueous solution. Absolutely true, hydrophobic molecules interact among them and they isolate from the environment.

7 0
3 years ago
How many grams of carbon (C) would be present in carbon monoxide (CO) that contains 2.666 grams of oxygen (O)? For example if th
oee [108]

Given :

Mass of oxygen containing carbon monoxide (CO) is 2.666 gram .

To Find :

How many grams of carbon (C) would be present in carbon monoxide (CO) that contains 2.666 grams of oxygen (O) .

Solution :

By law of constant composition , a given chemical compound always contains its component elements in fixed ratio (by mass) and does not depend on its source and method of preparation.

So , volume of solution does not matter .

Moles of oxygen , n=\dfrac{2.666}{16}=0.167\ mole .

Now , molecule of CO contains 1 mole of C .

So , moles of C is also 0.167 mole .

Mass of carbon , m=12\times 0.167=2\ g .

Therefore , mass of carbon is 2 grams .

Hence , this is the required solution .

5 0
3 years ago
Other questions:
  • A marine biologist is preparing a deep-sea submersible for a dive. The sub stores breathing air under high pressure in a spheric
    5·1 answer
  • A mole of ethyl alcohol weighs 46 g. how many grams of ethyl alcohol are needed to produce 1 l of a 2-millimolar (2 mm) solution
    13·1 answer
  • 7. What are the coefficients when the equation below is balanced?
    15·2 answers
  • !!!!!!!!!!!!!!!????<br> hElP!!!!!!!!!!!!
    8·2 answers
  • Pls help me with this atomic number worksheet I will make you the brainiest worth 25 points
    7·1 answer
  • What makes the desert unique from other biomes.
    14·1 answer
  • CaCO3 (s) + 2HCl (aq) → CaCl2 (aq) + CO2 (g) + H20 (1)
    6·1 answer
  • Why it is necessary for plants to have chloroplasts?<br><br> In your own words, please
    14·1 answer
  • All of the following affect toxicity of a substance except*
    9·2 answers
  • Please!!!!!!!!!!!!!!!!!!!!!!!
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!