Answer:
J'(-2,5)
K'(-7,5)
M'(-3.5,2)
L'(5.5,2)
Step-by-step explanation:
Please refer to the image attached to this answer.
Trapezoid JKLM is reflected over the x-axis, what do we notice about the ordered pairs of the original figure and the ordered pairs of its reflection over the x-axis is described below.
Point J , K L and M , when reflected over x axis , there distance from the y axis remains the same in second quadrant. the x coordinate becomes negative however the y coordinates remains the same.
The coordinates will be as shown in the image attached.
2+42/-2-5(-3) Multiply -5 and -3.
2+42/-2+15 Now, add the non fraction numbers. (2 and 15)
17+42/-2 Here, you want to reduce the fraction if you can, and yes, you can. Find the divisible number that is the lowest one that both can be evenly divided by. For this problem, it’s -2.
17-21. And from here, its easy. Just a simple subtraction problem.
-4 should be the correct answer.
Answer:
7/20
Step-by-step explanation:
There are 20 customers (the denominator) and 7 can pay cash (the numerator)
Answer:
EF is 16.
Step-by-step explanation:
So we know that Point E is somewhere on Line DF. In other words, DE plus EF must equal DF. In an equation, this is:
We are given that DE is 2x, EF is 2x-6, and DF is 3x+5. So, substitute:
Now, solve for x.
On the right, combine like terms:
Subtract 4x from both sides:
Subtract 5 from both sides:
Divide both sides by -1:
Now that we know x is 11, substitute this back into the equation for EF to find EF.
Substitute 11 for x:
Multiply:
Subtract:
And we're done!
