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pashok25 [27]
3 years ago
7

Find three consecutive odd integers whose sum is 129

Mathematics
1 answer:
viva [34]3 years ago
4 0

Answer:

41, 43, and 45,

Step-by-step explanation:

If you add them up you get 129

plz mark brainliest

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Which of these examples is an error of addition by one?
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Answer:

The correct answer is:

A. 27,465 +52,534 = 79,899

Step-by-step explanation:

Given are the options for addition

We have to check each addition one by one

So,

A. 27,465 +52,534 = 79,899

This option is the example of error of addition by one. The answer should have been 79,999. Hence there is an error in addition ..

Hence, option a: 27,465 +52,534 = 79,899  is the correct answer ..

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3 years ago
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If $190 is invested at an interest rate of 11% per year and is compounded continuously, how much will the investment be worth in
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answer is c) 295.01

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3 years ago
HELP PLS MARKING BRAINLEIST TO CORRECT ANSWER
Andreyy89

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Step-by-step explanation:

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3 years ago
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Give the boundaries of the indicated value.<br> 29.4 miles<br> The boundaries are<br> miles.
sineoko [7]

Answer:

The boundaries for the observed value, 42.8 miles are 42.75 miles up to 42.85 miles.

Step-by-step explanation:

hope it helps you friend ☺️

6 0
2 years ago
How can i differentiate this equation?
Dmitry_Shevchenko [17]

\bf y=\cfrac{2x^2-10x}{\sqrt{x}}\implies y=\cfrac{2x^2-10x}{x^{\frac{1}{2}}} \\\\\\ \cfrac{dy}{dx}=\stackrel{\textit{quotient rule}}{\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2}x^{-\frac{1}{2}} \right)}{\left( x^{\frac{1}{2}} \right)^2}} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~(2x^2-10x)\left( \frac{1}{2\sqrt{x}} \right)}{\left( x^{\frac{1}{2}} \right)^2} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x}


\bf\cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})~~-~~\left( \frac{2x^2-10x}{2\sqrt{x}} \right)}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{ \frac{(4x-10)(\sqrt{x})(2\sqrt{x})~~-~~(2x^2-10x)}{2\sqrt{x}}}{x} \\\\\\ \cfrac{dy}{dx}=\cfrac{(4x-10)(\sqrt{x})(2\sqrt{x})~~-~~(2x^2-10x)}{2x\sqrt{x}}


\bf \cfrac{dy}{dx}=\cfrac{(4x-10)2x~~-~~(2x^2-10x)}{2x\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{8x^2-20x~~-~~(2x^2-10x)}{2x\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{8x^2-20x~~-~~2x^2+10x}{2x\sqrt{x}} \implies \cfrac{dy}{dx}=\cfrac{6x^2-10x}{2x\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{2x(3x-5)}{2x\sqrt{x}}\implies \cfrac{dy}{dx}=\cfrac{3x-5}{\sqrt{x}}

8 0
3 years ago
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