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dexar [7]
3 years ago
13

Please solve the inequality for p 4p + 2 < 2(p + 5)

Mathematics
1 answer:
Alchen [17]3 years ago
7 0
(P Is Less Than 1.5) Is The Answer
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false

Step-by-step explanation:

-5,-4,-3,-2,-1,0,1,2,3,4,5

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Step-by-step explanation:

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Solve 15 ≥ -3x or x ≥ -2. <br> A{x | x ≤ -5} <br> B{x | x ≥ -5}<br> C {all reals}
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The answer for 15 <u>></u> -3x would be x <u>></u><u /> -5.

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3. Switch sides (x <u>></u> -5).

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A blood sample with a known glucose concentration of 102.0 mg/dL is used to test a new at home glucose monitor. The device is us
Soloha48 [4]

Answer:

The Absolute Error is the difference between the actual and measured value.

Absolute \:error = |Actual \:value - Measured \:value|

The Relative Error is the Absolute Error divided by the actual measurement.

Relative \:error = \frac{Absolute \:error}{Actual \:value}

We know that the actual value is 102.0 mg/dL.

To find the absolute error and relative error for each measurement made by the glucose monitor you must use the above definitions.

a) For a concentration of 104.5 mg/dL the absolute error and relative error are

Absolute \:error = \left|102-104.5\right|\\Absolute \:error =\left|-2.5\right|\\Absolute \:error =2.5

Relative \:error = \frac{2.5}{102.0}=0.0245

b) For a concentration of 96.2 mg/dL the absolute error and relative error are

Absolute \:error = \left|102.0-96.2\right|\\Absolute \:error =\left|5.8\right|\\Absolute \:error =5.8

Relative \:error = \frac{5.8}{102.0}=0.0569

c) For a concentration of 102.2 mg/dL the absolute error and relative error are

Absolute \:error = \left|102.0-102.2\right|\\Absolute \:error =\left|-0.2\right|\\Absolute \:error =0.2

Relative \:error = \frac{0.2}{102.0}=0.00196

d) For a concentration of 98.3 mg/dL the absolute error and relative error are

Absolute \:error = \left|102.0-98.3\right|\\Absolute \:error =\left|3.7\right|\\Absolute \:error =3.7

Relative \:error = \frac{3.7}{102.0}=0.0363

e) For a concentration of 101.8 mg/dL the absolute error and relative error are

Absolute \:error = \left|102.0-101.8\right|\\Absolute \:error =\left|0.2\right|\\Absolute \:error =0.2

Relative \:error = \frac{0.2}{102.0}=0.00196

4 0
3 years ago
Shane biked 1 mile less than three times the number of miles lissette biked. Shane biked a total of 7 miles. Write an equation t
ladessa [460]

Answer:

7x3=21-1=20

Step-by-step explanation:

The answer is 7x3=21-1=20

3 0
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