What is the product of all values of b that satisfy (b-2)(b-8) +4= 0 ?
1 answer:
Answer:
D
Step-by-step explanation:
(b-2)(b-8)+4=0
b^2-10b+16+4=0
b^2-10b+20=0
Product of roots is given by c/a=20. So the answer is 20
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