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Scrat [10]
3 years ago
15

4. Suppose that you have an enormous grapefruit that is 92% water (by weight). The grapefruit weights 100 pounds. If the water c

ontent of the grapefruit evaporates until it is 90% water (by weight), then approximately how much does the grapefruit now weigh?
Mathematics
1 answer:
Anton [14]3 years ago
8 0

Answer:

80 pounds.

Step-by-step explanation:

Let W₁ be the initial weight of water in the grapefruit, W₂ be the weight of water in the grapefruit after evaporation, and M be the total weight of the grapefruit after evaporation. Assuming that, originally, the grapefruit weighed 100 pounds with a 92% water content and the weight of the "non-water" part of the fruit (100 - W₁) does not change. The final weight of the grapefruit (M) is given by:

W_1=0.92*100=92\\W_2=0.90*M\\W_2+(100-W_1) = M\\W_2=M-8\\(1-0.9)M=8\\M=80

The grapefruit now weighs 80 pounds.

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Answer:

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Step-by-step explanation:

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We have

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P Q=(5,5,-3)

PR=<5,2,1> - <0,-4,0>

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The cross product of the two determined vector will produce an orthogonal to the plane

the cross product of two vectors is expressed as

(a,b,c) x (d,e,f)=(bf-c e, c d-a f, a e-b d)

going by the expansion above we have

P Q * PR =(5,5,-3) X (5,6,1) =(5-(-18), -15-5, 30-25)

P Q * PR =(23,-20,-5).

b. To determine the area, we use also use the cross product of the two formed vectors i.e

A=\frac{1}{2}|PQxPR|\\

A=\frac{1}{2}|(5,5,-3)x(5,6,1)|\\A=\frac{1}{2}|(23,-20,-5)|\\\\A=\frac{1}{2}\sqrt{23^{2}+20^{2}+5^{2}} \\A=\frac{1}{2}(30.9)\\A=15.4 unit square

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Step-by-step explanation:

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