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maw [93]
3 years ago
13

Citrus farmer who grows mandarin oranges finds that the diameters of mandarin oranges harvested on his farm follow a normal dist

ribution with a mean diameter of 5.85 cm and a standard deviation of 0.24 cm. Find the 80th percentile for the diameters of mandarin oranges, round 4 decimal places
Mathematics
1 answer:
SSSSS [86.1K]3 years ago
8 0

Answer:

6.0520

Step-by-step explanation:

Given that:

Mean = 5.85

Standard deviation = 0.24

Let N denote the 80th percentile.

P(X < N) = 0.8

P(Z < \dfrac{(N - 5.85)}{0.24}) = 0.8

Using the Excel formula: = NORM.INV(0.8,5.85,0.24)

The 80th percentile for the diameters of mandarin oranges:

= 6.0520 (to 4 decimal place)

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Just add 2/5+2/5+2/5.

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Add your numerators first: 2+2+2=6 

Leave your denominators alone they are all 5 so that's ok.

Your answer will be 6
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