The next step in assembling the coffee table is to attach a support from point D to point C, which is halfway down leg A.

In square $ABCD$, $E$ is the midpoint of $\overline{BC}$, and $F$ is the midpoint of $\overline{CD}$. Let $G$ be the intersectio

tamaranim1 [39]

Draw DH perpendicular to AE.

By the Side-Angle-Side postulate ΔABE = ΔBEF.

this is the enitre answer: https://web2.0calc.com/questions/in-square-abcd-e-is-the-midpoint-of-line-bc-and-f-is-the-midpoint-o...

8 0

2 years ago

What fraction of 60 is 90?<br> 50 POINTS OwO

maxonik [38]

Step-by-step explanation:

90 / 60 = 3/2

When you multiply 3/2 with 60, you get 90.

Hence 3/2 of 60 is 90.

4 0

3 years ago

How do I solve 2m + n = 2 and 3m - 2n = 3 using substitution?

Leona [35]

$\huge \boxed{\mathbb{QUESTION} \downarrow}$

Solve 2m + n = 2 and 3m - 2n = 3 using substitution.

$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

We can use the substitution method to solve linear equations of this form. Let's solve for m & n.

$\left. \begin{array} { l } { 2 m + n = 2 } \\ { 3 m - 2 n = 3 } \end{array} \right.$

To solve a pair of equations using substitution, first solve one of the equations for one of the variables. Then substitute the result for that variable in the other equation.

$2m+n=2, \: 3m-2n=3$

Choose one of the equations and solve it for m by isolating m on the left-hand side of the equal sign.

$2m+n=2$

Subtract n from both sides of the equation.

$2m=-n+2$

Divide both sides by 2.

$m=\frac{1}{2}\left(-n+2\right) \\$

Multiply 1/2 times -n+2.

$m=-\frac{1}{2}n+1 \\$

Substitute $-\frac{n}{2}+1\\$ for m in the other equation, 3m-2n=3.

$3\left(-\frac{1}{2}n+1\right)-2n=3 \\$

Multiply 3 times $-\frac{n}{2}+1\\$ .

$-\frac{3}{2}n+3-2n=3 \\$

Add $-\frac{3n}{2}\\$ to -2n.

$-\frac{7}{2}n+3=3 \\$

Subtract 3 from both sides of the equation.

$-\frac{7}{2}n=0 \\$

Divide both sides of the equation by $-\frac{7}{2}\\$ , which is the same as multiplying both sides by the reciprocal of the fraction.

$\large \underline{\underline{ \bf \: n=0 }}$

Substitute 0 for n in $m=-\frac{1}{2}n+1\\$ . Because the resulting equation contains only one variable, you can solve for m directly.

$\large \underline{ \underline{\bf \: m=1 }}$

The system is now solved.

$\huge \boxed{ \boxed{ \bf \: m=1, \: n=0 }}$

4 0

3 years ago

The path of a model rocket can be represented by the equation h(t)=-t2+15t+16, where h(t) is the height, in feet, of the rocket

Musya8 [376]

The height is 52 feet.

Using t=3, we have:
-3² + 15(3) + 16 = -9 + 45 + 16 = 52

4 0

3 years ago

Read 2 more answers

In a certain Algebra 2 class of 28 students, 11 of them play basketball and 13 of them play baseball. There are 11 students who

leonid [27]

Probability of a student playing both basketball and baseball is 7/28

Step-by-step explanation:

Step 1:

It is given the class has 28 students out of which 11 play basketball and 13 play baseball. It is also given that 11 students play neither sport.

Total number of students = 28

Students playing neither sport = 11

Students playing at least one sport = 28 - 11 = 17

Step 2:

Let N(Basketball) denote the number of students playing basketball and N(Baseball) denote the number of people playing baseball.

Then N(Basketball U Baseball) denotes the total number of students playing basketball and baseball and N(Basketball ∩ Baseball) denotes playing both basketball and baseball.

Since the number of students playing at least one sport is 17, N (Basketball U Baseball) = 17.

N (Basketball U Baseball) = N(Basketball) + N(Baseball) - N(Basketball ∩ Baseball)

N(Basketball ∩ Baseball) = N(Basketball) + N(Baseball) - N (Basketball U Baseball)

N(Basketball ∩ Baseball) = 11 + 13 - 17 = 7

Step 3:

Number of students playing both basketball and baseball = 7

Total number of students = 28

Probability of a student playing both basketball and baseball is 7/28

Step 4:

Answer:

Probability of a student playing both basketball and baseball is 7/28

3 0

2 years ago