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AleksandrR [38]
3 years ago
11

What are millimeters

Chemistry
2 answers:
Ann [662]3 years ago
6 0
The millimetre or millimeter is a unit of length in the metric system, equal to one thousandth of a metre, which is the SI base unit of length. Therefore, there are one thousand millimetres in a metre. There are ten millimetres in a centimetre.
DerKrebs [107]3 years ago
3 0
Millimeters are an SI unit of length that =0.0001 m
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Neurons- transmit nerve impulses. And Neuroglial cells- are non-conducting “support cells” of nervous tissue.

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The red arrow is pointed at different locations of an atom of Helium. Where is it pointing to the GREATEST concentration of atom
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Suppose a grill lighter contains 50.0 g of butane. How many grams of butane in the lighter would have to be burned to produce 17
Hitman42 [59]

<span>Answer is: mass of burned butane is 11.6 g.</span>

Chemical reaction: 2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O.

m(butane) = 50,0 g.

<span> V(CO</span>₂) = 17,9 L.<span>
n(CO</span>₂) = V(CO₂) ÷ Vm.<span>
n(CO</span>₂) = 17,9 L ÷ 22,4 L/mol.<span>
n(CO</span>₂) = 0,8 mol.<span>
From chemical reaction n(CO</span>₂) : n(C₄H₁₀) = 8 : 2.<span>
n(C</span>₄H₁₀) = 0,8 mol ÷ 4.<span>
n(C</span>₄H₁₀) = 0,2 mol.<span>
m(C</span>₄H₁₀) = n(C₄H₁₀) · M(C₄H₁₀).<span>
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5 0
4 years ago
A gas at a pressure of 2.0 atm is in a closed container. Indicate the changes (if any) in its volume when the pressure undergoes
garik1379 [7]

Answer:

a) The volume increases

b) The volume decreases

c) The volume does not change

Explanation:

<em>A gas at a pressure of 2.0 atm is in a closed container. Indicate the changes (if any) in its volume when the pressure undergoes the following changes at constant temperature and constant amount of gas.</em>

<em />

When there is a change in the pressure (P) at constant temperature (T) and amount of gas (n), we can find the change in the volume (V) using Boyle's law.

P₁.V₁ = P₂.V₂

where,

1 refer to the initial state

2 refer to the final state

<em>a) The pressure drops to 0.40 atm.</em>

P₁.V₁ = P₂.V₂

(2.0 atm) . V₁ = (0.40 atm) . V₂

V₂ = 5 . V₁

The volume increases.

<em>b) The pressure increases to 6.0 atm.</em>

P₁.V₁ = P₂.V₂

(2.0 atm) . V₁ = (6.0 atm) . V₂

V₂ = 0.33 . V₁

The volume decreases.

<em>c) The pressure remains at 2.0 atm.</em>

P₁.V₁ = P₂.V₂

(2.0 atm) . V₁ = (2.0 atm) . V₂

V₂ = V₁

The volume does not change.

4 0
3 years ago
Standard temperature and<br> pressure (STP) is 273 Kand<br> [?] atm.
alisha [4.7K]

Answer:

Explanation:

273K

1ATM

6 0
3 years ago
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