The halogens and noble gases are alike because they are all non-metallic elements, with the exception of astatine, a radioactive
Answer:
i cant see the whats in the picture
Answer:
The answer is "3.81041978"
Explanation:
![\to 1 \ OZ= 28.349523125 \ grams\\\\](https://tex.z-dn.net/?f=%5Cto%201%20%5C%20OZ%3D%2028.349523125%20%5C%20grams%5C%5C%5C%5C)
![=28.349523125\times {1000} \ miligrams\\\\= 28349. 5231 \ miligrams\\](https://tex.z-dn.net/?f=%3D28.349523125%5Ctimes%20%7B1000%7D%20%5C%20miligrams%5C%5C%5C%5C%3D%2028349.%205231%20%20%5C%20miligrams%5C%5C)
In 1860 ![= 28349.5231 \ miligrams\\](https://tex.z-dn.net/?f=%3D%2028349.5231%20%5C%20miligrams%5C%5C)
![\to In \$ \ 1 = \frac{28349.5231}{1860} \ \ miligrams\\](https://tex.z-dn.net/?f=%5Cto%20In%20%5C%24%20%5C%201%20%3D%20%5Cfrac%7B28349.5231%7D%7B1860%7D%20%5C%20%5C%20miligrams%5C%5C)
![= 15.2416791 \ miligrams](https://tex.z-dn.net/?f=%3D%2015.2416791%20%5C%20miligrams)
![\ In \ 1 \ quarter = \$ \ 0.25](https://tex.z-dn.net/?f=%5C%20In%20%5C%20%201%20%5C%20quarter%20%3D%20%20%5C%24%20%5C%200.25)
![\to \$ \ 0.25 = 15.2416791 \times 0.25 \ miligrams\\](https://tex.z-dn.net/?f=%5Cto%20%5C%24%20%5C%200.25%20%3D%20%2015.2416791%20%20%5Ctimes%200.25%20%5C%20%20miligrams%5C%5C)
![= 3.81041978](https://tex.z-dn.net/?f=%3D%203.81041978)
C3H8+3O2--->3CO2+8H
Therefore for every 1:3 there are 3 Carbon dioxides that form. That means find the limiting reactant from the two reactants.
5.5g(1mole C3H8/44.03g of C3H8)=0.1249 moled of C3H8 and if for every one C3H8 we can form three CO2. We can assume 0.3747 miles of CO2 will be produced.
15g of O2(1 mole O2/32g of O2)=0.4685moles O2 and if for every three O2 we can produce three CO2 we may assume a 1:1 ratio.
This means C3H8 will be your limiting reactant. Therefore 0.3747 moles of CO2 will be produced.
0.3747 moles of CO2(48.01 g of CO2/1 mole of CO2)= 17.99 grams of CO2