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NeTakaya
3 years ago
7

Al of the following are common automotive network configurations EXCEPT:

Engineering
1 answer:
qwelly [4]3 years ago
4 0

Answer:

Option D

triangle series

Explanation:

Some of the common automotive network configurations include looped series configuration and star parallel. Moreover, bussed parallel network configuration is also used in automotive. However, there's no any network configuration called triangle series.

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Mihuv8tr5qwertgyhjzxcvbnfr5y7nnbvcxzwertgyhujio vv solve the riddle
Inessa [10]

Answer:

v1QAZ3EDCRFV5TGB6YHNUJMIK,9OL0K9MIJNUHB7YGVTFCRDXESZWAq

Explanation:

qaAQzwsxedcnujmik,ol mkjuhtfcrxdZSWAQWSEDRFTGYHUJIKO,LP.; ,LMKJNUHTGDXESZWaEDRFTGHJKL,MNBVFDSWQAAWERTYUIOP;L,MNHGFDEWwertyuikolp;[l.,mnbvfre345678990098765434rtyhnbhju8765rtghjui875rfghji8765rfghju7654redfghu7643erfghji987yhjko987y

4 0
3 years ago
Read 2 more answers
The primary heat transfer mechanism that quickly warms my hand if I hold it directly above a campfire is: a)-Radiation b)-Induct
Tanzania [10]

Answer:

The correct answer is option 'c':Convection.

Explanation:

When we ignite a campfire the heat produced by combustion heats the air above the fire. As we know that if a gases gains heat it expands thus it's density decreases and hence it rises, if we hold our hands directly above the fire this rising hot air comes in contact with our hands thus warming them.

The situation is different if we are at some distance from the campfire laterally. Since the rising air cannot move laterally the only means the heat of the fire reaches our body is radiation.

But in the given situation the correct answer is convection.  

6 0
3 years ago
Consider the time domain waveforms below on the left. Match waveforms (a) - (e) to their respective frequency spectrum represent
lozanna [386]

Answer:

(a) ------(3). (b)------(1) (c)-----(5) (d)------(2) ------ (e) -----4

Note: Kindly find an attached copy of the diagram associated with the solution to the question below.

Sources: the diagram to this question was researched from Quizlet

Explanation:

Solution

(1) Part (a)a waveform has a high frequency components compared to another waveform. the corresponding frequency components should be high.

So for the wave form a  the corresponding frequency spectrum is (3)

(2) For part (b), waveform has three harmonics, the corresponding frequency spectrum is (1)

(3) The time domain waveform plot (c) is a sine wave but there exists a dc component.

Thus x[0] ≠0

For (c) the corresponding frequency spectrum is (5)

(4) For part (d) the corresponding frequency spectrum is (2)

(5) A sine wave is made of a single frequency only and its spectrum is a single point

For (e) the corresponding frequency spectrum is (4)

3 0
3 years ago
What type of slab and beam used in construction of space neddle​
Sav [38]

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5 0
3 years ago
You will create an array manipulation program that allows the user to do pretty much whatever they want to an array. When launch
enyata [817]

Answer:

Check the explanation

Explanation:

#include <iostream>

using namespace std;

void insert(int* arr, int* size, int value, int position){

if(position<0 || position>=*size){

cout<<"position is greater than size of the array"<<endl;

return ;

}

*size = *size + 1 ;

for(int i=*size;i>position;i--){

arr[i] = arr[i-1];

}

arr[position] = value ;

}

void print(int arr[], int size){

for(int i=0;i<size;i++){

cout<< arr[i] <<" ";

}

cout<<" "<<endl;

}

void remove(int* arr, int* size, int position){

* size = * size - 1 ;

for(int i=position;i<*size;i++){

arr[i] = arr[i+1];

}

}

int count(int arr[], int size, int target){

int total = 0 ;

for(int i=0;i<size;i++){

if(arr[i] == target)

total += 1 ;

}

return total ;

}

int main()

{

int size;

cout<<"Enter the initial size of the array:";

cin>>size;

int arr[size],val;

cout<<"Enter the values to fill the array:"<<endl;

for(int i=0;i<size;i++){

cin>>val;

arr[i] = val ;

}

int choice = 5,value,position,target ;

do{

cout<<"Make a selection:"<<endl;

cout<<"1) Insert"<<endl;

cout<<"2) Remove"<<endl;

cout<<"3) Count"<<endl;

cout<<"4) Print"<<endl;

cout<<"5) Exit"<<endl;

cout<<"Choice:";

cin>>choice;

switch(choice){

case 1:

cout << "Enter the value:";

cin>>value;

cout << "Enter the position:";

cin>>position;

insert(arr,&size,value,position);

break;

case 2:

cout << "Enter the position:";

cin>>position;

remove(arr,&size,position);

break;

case 3:

cout<<"Enter the target value:";

cin>>target;

cout <<"The number of times "<<target<<" occured in your array is:" <<count(arr,size,target)<<endl;

break;

case 4:

print(arr,size);

break;

case 5:

cout <<"Thank you..."<<endl;

break;

default:

cout << "Invalid choice..."<<endl;

}

}while(choice!=5);

return 0;

}

Kindly check the attached images below for the code output.

3 0
4 years ago
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