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2 years ago

List all the qualities of an engineer?

Engineering

1 answer:

Dennis_Churaev [7]2 years ago

6 0

Answer:

Math and Computer Skills. A qualified engineer should be good at math, at least through the level of calculus and trigonometry, and understand the importance of following the data when making design decisions.

Organization and Attention to Detail.

Curiosity.

Creativity.

Critical Thinking.

Intuition.

Explanation:

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Technician A says that when the malfunction indicator light or service engine light is on you should retrieve the diagnostic tro

sergiy2304 [10]

Answer: A.

Explanation: Which of the following types of data helps a tech to determine the actual conditions under which a fault code is set? a test light. When it comes to troubleshooting an on-board diagnostic (OBD) code, the tech's best tools include all of these EXCEPT: ... original equipment manufacturer (OEM) diagnostic flow charts.

8 0

3 years ago

Define, in words the following i relative humidity ii) dew point temperature

defon

Explanation:

i) When we divide water vapor's partial pressure by the water's equilibrium vapor pressure at a given temperature we get relative humidity.

It is denoted by ∅

$\phi ={\frac {p_ {H_{2}O} }{p_{H_{2}O} ^{*}}}$

ii) When air is cooled so that it becomes saturated with water vapor the temperature where this occurs is called the dew point.

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3 years ago

A composite wall is composed of 20 cm of concrete block with k = 0.5 W/m-K and 5 cm of foam insulation with k = 0.03 W/m-K. The

wariber [46]

Answer:

4.8°C

Explanation:

The rate of heat transfer through the wall is given by:

$q=\frac{Ak}{L}dT$

$\frac{q}{A}=\frac{k}{L}dT$

Assumptions:

1) the system is at equilibrium

2) the heat transfer from foam side to interface and interface to block side is equal. There is no heat retention at any point

3) the external surface of the wall (concrete block side) is large enough that all heat is dissipated and there is no increase in temperature of the air on that side

${k_{fi}= 0.03 W/m.K$

${L_{fi}= 5 cm = 0.05 m$

${T_{fi}= 25 \°C$

${k_{cb} = 0.5 W/m.K$

${L_{cb}= 20 cm = 0.20 m$

${T_{cb}= 0 \°C$

${T_{m}= ? \°C =$ temperature at the interface

Solving for ${T_{m}$ will give the temperature at the interface:

$\frac{q}{A}=\frac{k_{fi} }{L_{fi} }(T_{fi} -T_{m})=\frac{k_{cb} }{L_{cb} }(T_{m} -T_{cb})$

$\frac{0.03}{0.05 }(25 -T_{m})=\frac{0.5}{0.2}(T_{m} -0})$

$15 -0.6T_{m}=2.5T_{m}$

$3.1T_{m}=15$

$T_{m}=4.8$

3 0

3 years ago

A battery with an f.e.m. of 12 V and negligible internal resistance is connected to a resistor of 545 How much energy is dissipa

Alenkasestr [34]

Answer:

When are resistors in series? Resistors are in series whenever the flow of charge, called the current, must flow through devices sequentially. For example, if current flows through a person holding a screwdriver and into the Earth, then

in Figure 1(a) could be the resistance of the screwdriver’s shaft,

the resistance of its handle,

the person’s body resistance, and

the resistance of her shoes.

Figure 2 shows resistors in series connected to a voltage source. It seems reasonable that the total resistance is the sum of the individual resistances, considering that the current has to pass through each resistor in sequence. (This fact would be an advantage to a person wishing to avoid an electrical shock, who could reduce the current by wearing high-resistance rubber-soled shoes. It could be a disadvantage if one of the resistances were a faulty high-resistance cord to an appliance that would reduce the operating current.)

Two electrical circuits are compared. The first one has three resistors, R sub one, R sub two, and R sub three, connected in series with a voltage source V to form a closed circuit. The first circuit is equivalent to the second circuit, which has a single resistor R sub s connected to a voltage source V. Both circuits carry a current I, which starts from the positive end of the voltage source and moves in a clockwise direction around the circuit.

Figure 2. Three resistors connected in series to a battery (left) and the equivalent single or series resistance (right).

To verify that resistances in series do indeed add, let us consider the loss of electrical power, called a voltage drop, in each resistor in Figure 2.

According to Ohm’s law, the voltage drop,

, across a resistor when a current flows through it is calculated using the equation

, where

equals the current in amps (A) and

is the resistance in ohms

(

)

. Another way to think of this is that

is the voltage necessary to make a current

flow through a resistance

So the voltage drop across

, that across

, and that across

. The sum of these voltages equals the voltage output of the source; that is,

This equation is based on the conservation of energy and conservation of charge. Electrical potential energy can be described by the equation

, where

is the electric charge and

is the voltage. Thus the energy supplied by the source is

, while that dissipated by the resistors is

Explanation:

8 0

3 years ago

The device whose operation closely matches the way the clamp-on ammeter works is

Ivanshal [37]

Answer:

The answer is

C. Split phase motor

Explanation:

Clamp meters rely on the principle of magnetic induction to make non contact AC current measurements. Electric current flowing through a wire produces a magnetic field.

Which is similar to basic mode of operation of electric motor and split phase motor is a type of electric motor.

What is a a clamp on meter?

Clamp meters are electrical testers which have wide jaws that are able to clamp around an electrical conductor. Originally designed as a single purpose tool for measuring AC current, clamp meters now include inputs for accepting test leads and other probes that support a wide range of electrical measurements, the jaws of a clamp meter permit work in tight spaces and permits current measurements on live conductors without circuit interruption.

6 0

3 years ago