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irakobra [83]
2 years ago
8

List all the qualities of an engineer?

Engineering
1 answer:
Dennis_Churaev [7]2 years ago
6 0

Answer:

Math and Computer Skills. A qualified engineer should be good at math, at least through the level of calculus and trigonometry, and understand the importance of following the data when making design decisions.

Organization and Attention to Detail.  

Curiosity.  

Creativity.  

Critical Thinking.

Intuition.

Explanation:

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Which of the following uses pressure and flow to transmit power from one location to another?
lord [1]

Answer:

fluid power

Explanation:

fluids commonly used in fluid power are Oil, Water, Air, CO², and Nitrogen gas, fluid power is commonly confused with hydraulic power, which only uses liquids, fluid power uses either liquids or gases

5 0
2 years ago
For this problem, calculate the following by hand and show the procedure for how you obtained the results. Subsequently, solve p
Gemiola [76]

Answer:wat

Explanation:

4 0
3 years ago
A common procedure for measuring the velocity of an air stream involves insertion of an electrically heated wire (called a hot-w
timurjin [86]

Answer:

V = 6.33 m/s

Explanation:

Given:

- The length of the wire L = 0.02 m

- The diameter of the wire D = 0.0005 m

- The calibration expression V = 0.0000625*h^2

- Environment temperature T_inf = 298 K

- Surface temperature T_s = 348 K

- The voltage drop dV = 5 V

- The electric current I = 0.1 A

Find:

- the velocity of Air

Solution:

- Calculate the surface area of the wire:

                             A = pi*D*L

                             A = pi*(0.0005)*(0.02) = 0.00003142 m^2

- The rate of energy in the wire P:

                             P = I*dV = 0.1*5 = 0.5 W

- Apply Newton's Law of Cooling:

                            P = h*A*(T_s - T_inf)

                            h =  P /A*(T_s - T_inf)

Plug in the values:

                             h= 0.5/ 0.00003142*(348 - 298)

                             h = 318.27 W /m^2K

- Using the calibration relationship given, compute the velocity of air:

                             V = 6.25*10^-5 * h^2

                             V = 6.25*10^-5 * (318.27)^2

                             V = 6.33 m/s

5 0
3 years ago
Water flows in a constant diameter pipe with the following conditions measured:
Burka [1]

Answer:

a) h_L=-3.331ft

b) The flow would be going from section (b) to section (a)

Explanation:

1) Notation

p_a =31.1psi=4478.4\frac{lb}{ft^2}

p_b =27.3psi=3931.2\frac{lb}{ft^2}

For above conversions we use the conversion factor 1psi=144\frac{lb}{ft^2}

z_a =56.7ft

z_a =68.8ft

h_L =? head loss from section

2) Formulas and definitions

For this case we can apply the Bernoulli equation between the sections given (a) and (b). Is important to remember that this equation allows en energy balance since represent the sum of all the energies in a fluid, and this sum need to be constant at any point selected.

The formula is given by:

\frac{p_a}{\gamma}+\frac{V_a^2}{2g}+z_a =\frac{p_b}{\gamma}+\frac{V_b^2}{2g}+z_b +h_L

Since we have a constant section on the piple we have the same area and flow, then the velocities at point (a) and (b) would be the same, and we have just this expression:

\frac{p_a}{\gamma}+z_a =\frac{p_b}{\gamma}+z_b +h_L

3)Part a

And on this case we have all the values in order to replace and solve for h_L

\frac{4478.4\frac{lb}{ft^2}}{62.4\frac{lb}{ft^3}}+56.7ft=\frac{3931.2\frac{lb}{ft^2}}{62.4\frac{lb}{ft^3}}+68.8ft +h_L

h_L=(71.769+56.7-63-68.8)ft=-3.331ft

4)Part b

Analyzing the value obtained for \h_L is a negative value, so on this case this means that the flow would be going from section (b) to section (a).

5 0
3 years ago
HELE
Neporo4naja [7]

Answer:

D The answer would be D $270

Explanation:

Hope this helps. Please mark me Brainliest

6 0
3 years ago
Read 2 more answers
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