Answer:
The viscosities of the oils are 0.967 Pa.s and 1.933 Pa.s
Explanation:
Assuming the two oils are Newtonian fluids.
From Newton's law of viscosity for Newtonian fluids, we know that the shear stress is proportional to the velocity gradient with the viscosity serving as the constant of proportionality.
τ = μ (∂v/∂y)
There are oils above and below the plate, so we can write this expression for the both cases.
τ₁ = μ₁ (∂v/∂y)
τ₂ = μ₂ (∂v/∂y)
dv = 0.3 m/s
dy = (0.06/2) = 0.03 m (the plate is centered in a gap of width 0.06 m)
τ₁ = μ₁ (0.3/0.03) = 10μ₁
τ₂ = μ₂ (0.3/0.03) = 10μ₂
But the shear stress on the plate is given as 29 N per square meter.
τ = 29 N/m²
But this stress is a sum of stress due to both shear stress above and below the plate
τ = τ₁ + τ₂ = 10μ₁ + 10μ₂ = 29
But it is also given that one viscosity is twice the other
μ₁ = 2μ₂
10μ₁ + 10μ₂ = 29
10(2μ₂) + 10μ₂ = 29
30μ₂ = 29
μ₂ = (29/30) = 0.967 Pa.s
μ₁ = 2μ₂ = 2 × 0.967 = 1.933 Pa.s
Hope this Helps!!!
The answer is E to increase the shear strength of the beam beyond that provided by the concrete
Answer:
It helps ensure the security of client data.
Explanation:
Cloud computing is one of the security features in networking which is being adopted by big corporations and organizations inorder to ensure smooth running of the organization.
Also, due to the sensitivity of data which some organizations deals in, they tried everything possible to protect themselves and their clients' information through use of cloud computing.<em> Data are stored in the clouds, and requires special administrative rights for it to be accessed by some of the staffs working in any given organization.</em>
Answer:
The diffusion coefficients for iron in nickel are given at two temperatures:
T (K) 1273 1473
D (
/s) 9.4 × 
2.4 × 
(a) Determine the values of Do and the activation energy Qd.
(b) What is the magnitude of D at 1100°C (1373 K)?
<em>A </em>
<em>The pre-exponential factor Do = 2.1 x </em><em></em>
<em>The activation energy Qd = 252,609 J/mol</em>
<em>B</em>
<em>The diffusion coefficient D= 5.14 x </em>
<em></em>
Explanation:
The full explanation is contained in the attached images;
Answer:
Logarithmic decrement is equal to 0.182
Explanation:
given,
amplitude decay = 9 dB
number of cycles = 12 cycles
mass of the system = 7 kg
spring stiffness = 3000 N/m
logarithmic decrement = ?
now,
logarithmic decreament = 
= 
=ln (1.2)
= 0.182
Hence, Logarithmic decrement is equal to 0.182
