<h2>
Answer:</h2>
7532V
<h2>
Explanation:</h2>
For a given transformer, the ratio of the number of turns in its primary coil () to the number of turns in its secondary coil () is equal to the ratio of the input voltage () to the output voltage () of the transformer. i.e
= ----------------(i)
<em>From the question;</em>
= number of turns in the primary coil = 8 turns
= number of turns in the secondary coil = 515 turns
= input voltage = 117V
<em>Substitute these values into equation (i) as follows;</em>
=
<em>Solve for </em><em>;</em>
= 117 x 515 / 8
= 7532V
Therefore, the output voltage (in V) of the transformer is 7532
Answer:
A) β_max = 20.64
B) TH = 68.25°C
C) TC = 54.27°C
Explanation:
A) We are given;
TH = 16°C = 16 + 273K = 289K
TC = 2°C = 2 + 273K = 275K
Formula for maximum cycle coefficient of performance is given as;
β_max = TH/(TH - TC)
β_max = 289/(288 - 275)
β_max = 20.64
B) We are given;
Heat rejected to system at hot reservoir; Q_H = 10.5 KW
Heat provided to system at cold reservoir; Q_C = 8.75 KW
Cold reservoir temperature; TC = 0°C = 0 + 273K = 273K
Formula for actual cycle COP is given as;
β_actual = Q_C/W_cycle
Where W_cycle is the work done and is given by;
W_cycle = Q_H - Q_C
W_cycle = 10.5 - 8.75 = 1.75 KW
Thus,
β_actual = 8.75/1.75
β_actual = 5
Actual cycle COP is defined as;
β_actual = TH/(TH - TC)
And we are looking for TH.
Thus,
TH = TC/(1 - (1/β_actual))
TH = 273/(1 - 1/5)
TH = 273/(4/5)
TH = 341.25K = 341.25 - 273°C = 68.25°C
C) We are given;
TH = 27°C = 27 + 273 = 300°C
β_max = 12
Thus, from,
β_max = TH/(TH - TC)
TC = TH(1 - (1/β_max))
TC = 300/(1 - 1/12)
TC = 327.27K = 327.27 - 273 °C = 54.27°C
Times the radius squared !
hope this helps :)))
Answer: Service and/or product line
Answer:
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